4x + 1 = 5, find x assuming x is a whole number

Mathematics

1 answer:

levacccp [35]3 years ago

4 0

Answer:

x=1

Step-by-step explanation:

4x+1=5

4x=5-1

4x=4

x=4/4=1

This happens to be a whole number.

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The ages of three children in a family can be expressed as consecutive integers. The square of the age of the youngest child is

tensa zangetsu [6.8K]

Answer: 10, 11, & 12

<u>Step-by-step explanation:</u>

Let x represent the age of the youngest child.

Their ages are consecutive so,

Youngest: x

Middle: x + 1

Oldest: x + 2

The age of the Youngest squared (x²) equals 8 times the Oldest [8(x + 2)] plus 4.

x² = 8(x + 2) + 4

x² = 8x + 16 + 4

x² = 8x + 20

x² - 8x - 20 = 0

(x - 10)(x + 2) = 0

x - 10 = 0 or x + 2 = 0

x = 10 or x = -2

Since age cannot be negative, x = -2 is not valid

So, the Youngest (x) is 10

the Middle (x + 1) is 11

and the Oldest (x + 2) is 12

4 0

3 years ago

Help ASAP solve: -3/4n = -6

anyanavicka [17]

Answer:

$\huge\boxed{n=8}$

Step-by-step explanation:

$-\dfrac{3}{4}n=-6\qquad|\text{multiply both sides by (-4)}\\\\(-4\!\!\!\!\diagup)\left(-\dfrac{3}{4\!\!\!\!\diagup}n\right)=(-4)(-6)\\\\3n=24\qquad|\text{divide both sides by 3}\\\\\dfrac{3\!\!\!\!\diagup n}{3\!\!\!\!\diagup}=\dfrac{24\!\!\!\!\!\diagup}{3\!\!\!\!\diagup}\\\\n=8$