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3 years ago

A car wash attendant counted the number of cars washed and the total amount of money earned. The

Mathematics

1 answer:

Gemiola [76]3 years ago

8 0

Answer:

total=n÷m $165÷15,$231÷21 and $275÷25

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Find the difference between 1.97 and 20

cestrela7 [59]

Answer:

1.97-20= -18.03

20-1.97= 18.03

Step-by-step explanation:subtract the numbers from each other.

6 0

3 years ago

If you can help 1-12 that’s great if not just help with what you can thanks

bearhunter [10]

(1. -2) (2. 0) (3. 6) (4. 3)

5 0

3 years ago

A guide wire for a palm tree makes a 32°angle with the ground and is staked 6 feet from the base of the tree. What is the length

labwork [276]

Answer:

b) 8.5 feet

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I need help on this question so if u actually can answer it correctly and show how you got it that would be helpful thx

Sedaia [141]

$\rm \looparrowright - \frac{1}{4} (8 - 4 + 20x)$

Subtract the numbers

$\rm \looparrowright - \frac{1}{4} (4+ 20x)$

Factor out 4 from the expression

$\rm \looparrowright - \frac{1}{ \cancel4} \times \cancel4(1 + 5x)$

$\rm \looparrowright - (1 + 5x)$

When there is a - in front of an expression in parentheses, change the sign of each term in the expression to -

$\rm \looparrowright - 1 - 5x$

Thus, Options A and F are correct!!~

6 0

3 years ago

Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein

Bad White [126]

Answer:

The rate at which water is being pumped into the tank is 13,913.27 cubic centimetre per minute

Step-by-step explanation:

Given that, the height of the conical tank is 13 meters and diameter is 3 meters.

Radius = $\frac32$ meters

$\therefore \frac{radius }{height}=\frac {\frac{3}{2}}{13}$

$\Rightarrow \frac{radius }{height}=\frac {3}{26}$

$\Rightarrow radius=\frac {3}{26}\times height$ ......(1)

The volume of the cone is $V=\frac13 \pi r^2 h$

Now putting $r=\frac{3}{26} h$

$V=\frac13 \pi (\frac3{26}h)^2 h$

$\Rightarrow V=\frac{3}{676} \pi h^3$

Differentiating with respect to t

$\frac{dV}{dt}=\frac{3}{676}\pi .3h^2 \frac{dh}{dt}$

$\Rightarrow \frac{dV}{dt}=\frac{9}{676}\pi h^2 \frac{dh}{dt}$

Given that, the water level is rising at a rate of 17 cm per minute when the height 1 meter= 100 cm .i.e $\frac{dh}{dt}=17$ cm/min

Putting $\frac{dh}{dt}=17$

$\frac{dV}{dt}=\frac{9}{676}\pi h^2 \times 17$

$\frac{dV}{dt}|_{h=100}=\frac{9}{676}\pi (100)^2 \times 17$

≈7,113 cubic centimetre per minute

The volume of water increases 7,113 cubic centimetre per minute while 6,800 cubic centimetre per minute is leaking out.

It means the required rate at which water is being pumped into the tank is

=(7,113+6,800)cubic centimetre per minute

=13,913 cubic centimetre per minute

4 0

4 years ago