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melamori03 [73]
3 years ago
10

Find the value of x, will give brainlist

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer:

7

Step-by-step explanation:

KU=UM

3x+3=4x-4

x= 7

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6 mi<br> 3 mi<br> 4+ 5+ 6+8+4+3<br> Total count →<br> -<br> mi<br> Mean Value
Olin [163]

Answer: The answer is 30

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3 years ago
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On a baseball field, the pitcher’s mound is 60.5 feet from home plate. During practice, a batter hits a ball 195 feet at an angl
worty [1.4K]

In this problem, we can imagine that all the points connect to form a triangle. The three point or vertices are located on the pitcher mount, the home plate and where the outfielder catches the ball. So in this case we are given two sides of the triangle and the angle in between the two sides.

<span>With the following conditions, we can use the cosine law to solve for the unknown 3rd side. The formula is:</span>

c^2 = a^2 + b^2 – 2 a b cos θ

Where,

a = 60.5 ft

b = 195 ft

θ = 32°

Substituting the given values:

c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32

c^2 = 3660.25 + 38025 – 20009.7

c^2 = 21,675.56

c = 147.23 ft

<span>Therefore the outfielder throws the ball at a distance of 147.23 ft towards the home plate.</span>

8 0
3 years ago
Divide x to the 5 eighths power divided by x to the 1 fourth power.
8_murik_8 [283]

\frac{x^{5/8}}{x^{1/4}} = x^{5/8-1/4}= x^{5/8-2/8}= x^{3/8}   or  \sqrt[8]{x^3}

8 0
3 years ago
PLEASE HELP ME WITH THIS
Harrizon [31]

Answer:

The last option.

Step-by-step explanation:

Hope this helps!

Wait hold on

6 0
4 years ago
Hiran invests 20 000 rupees in an account for 3 years at 1.5% per year compound interest.
svp [43]

Answer:

There will be 20 914 rupees in the amount at the end of 3 years.

Step-by-step explanation:

The amount of rupes after t years in compound interest is given by:

A(t) = A(0)(1+r)^{t}

In which A(0) is the initial amount and r is the interest rate, as a decimal.

Hiran invests 20 000 rupees in an account for 3 years at 1.5% per year compound interest.

This means that A(0) = 20000, r = 0.015. So

A(t) = A(0)(1+r)^{t}

A(t) = 20000(1+0.015)^{t}

A(t) = 20000(1.015)^{t}

Work out the total amount of money in the account at the end of 3 years.

This is A(3). So

A(3) = 20000(1.015)^{3} = 20913.6

Rounding to the nearest rupee.

There will be 20 914 rupees in the amount at the end of 3 years.

8 0
3 years ago
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