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alukav5142 [94]
2 years ago
10

What polynomial must be added to 3x2 + 4x + 7 to obtain the sum of 0?

Mathematics
1 answer:
Dovator [93]2 years ago
5 0

Answer:

do (3x2+4x+7)+y=0

y=-3x^2-4x-7

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Three taps can fill a tank in 1.5 hours how many tab can feel it in 45 minutes ​
kap26 [50]

Answer:

30 Tabs?

Step-by-step explanation:

Not so sure on this, I just divided 45/1.5.

5 0
2 years ago
A cone with radius 2 and height 9 has its radius tripled. How many times greater is the volume of the larger cone than the small
SpyIntel [72]

Answer:

When increasing the radius 3 times the volume increases 9 times and when it is reduced to a third the volume decreases 9 times

Step-by-step explanation:

We have that the formula for the volume of a cone is:

Vc = pi * (r ^ 2) * h

We first calculate the original volume, where the radius is 2 and the height is 9, replacing:

Vc = 3.14 * (2 ^ 2) * 9

Vc = 113.04

Now if the radius is tripled it would be: 2 * 3 = 6, the radius would be 6, replacing:

Vc = 3.14 * (6 ^ 2) * 9

Vc = 1017.36

If we compare:

1017.36 / 113.04 = 9

This means that when the radius is tripled, the volume increases 9 times.

When if re reduces to a third the radius would be: 2/3, replacing:

Vc = 3.14 * ((2/3) ^ 2) * 9

Vc = 12.56

113.04 / 12.56 = 9

Which means that by reducing it to a third the volume becomes 9 times smaller.

6 0
3 years ago
Please help, I would appreciate it a lot
AleksAgata [21]

Answer:

Sry, Can't help.

It's soo hard!!

8 0
3 years ago
What is 377,060 written in expanded form using exponents
Zinaida [17]
3x10^5
+7x10^4
+7x10^3
+0x10^2
+6x10^1
+0x10^0
7 0
3 years ago
If you are dealt 4 cards from a shuffled deck of 52 cards, find the probability of getting two queens and two kings.
Bingel [31]

<u>Given</u>:

If you are dealt 4 cards from a shuffled deck of 52 cards.

We need to determine the probability of getting two queens and two kings.

<u>Probability of getting two queens and two kings:</u>

The number of ways of getting two queens is 4C_2

The number of ways of getting two kings is 4C_2

Total number of cases is 52C_4

The probability of getting two queens and two kings is given by

\text {probability}=\frac{\text {No.of fanourable cases}}{\text {Total no.of cases}}

Substituting the values, we get;

probability=\frac{4C_2 \cdot 4C_2}{52C_4}

Simplifying, we get;

probability=\frac{6 (6)}{270725}

probability=\frac{36}{270725}

probability=0.000133

Thus, the probability of getting two queens and two kings is 0.000133

7 0
3 years ago
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