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likoan [24]
4 years ago
11

I ;UNEED AUNSWER ASAPS Out of 45 times at bat, Raul got 19 hits. Find Raul’s batting average as a decimal rounded to the nearest

thousandth.
Mathematics
1 answer:
tekilochka [14]4 years ago
4 0

Answer:

2.368

Step-by-step explanation:

45/19=2.368

You might be interested in
1. Suppose D has a coordinate of 11 and DE = 5. What are the possible<br> midpoints of DE?
Rasek [7]

Answer:

The possible midpoints are (5.5,8) and (5.5,3)

Step-by-step explanation:

Given

D = 11

DE = 5

Required

Determine the midpoint of DE

First, we need to determine the coordinates of E

If E is to the right of DE;

E - D = 5

E - 11 = 5

E = 11 + 5

E = 16

Hence, the coordinate is (11,16)

Midpoint = \frac{1}{2} * (11,16)

Midpoint =  (5.5,8)

Else:

D - E = 5

11 - E = 5

E = 11 - 5

E = 6

Hence, the coordinate is (11,6)

Midpoint = \frac{1}{2} * (11,6)

Midpoint = (5.5,3)

<em>The possible midpoints are (5.5,8) and (5.5,3)</em>

6 0
3 years ago
A model of a plane has a length of 17cm. the scale of the model is 1 : 200 work out the length of the real plane give your answe
vlada-n [284]
So if 1 CM in the model is 200 CM in the actual, just 200 x 17 which is 3400cm
so in Meters it would be 34 m
3 0
4 years ago
Which set of side length form a right triangle?
goldfiish [28.3K]

B. 15ft, 36ft, 39ft

use pythagorean theorem

a²+b²=c²

225+1296=1521

6 0
3 years ago
The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room.
Dahasolnce [82]

Answer:

Option B , C  and E are correct

y^2-5y =750

750 -y(y-5)=0

(y+25)(y-30)=0

Step-by-step explanation:

Given : Area of rectangular room is 750 square feet.

Width of the room is 5 feet less than the length of the room.

Let y be the length of the room

then,

As per the given condition

width of the room is: y-5

Area of rectangle is multiply the length by its width.

Area of rectangle = length \times width

Substitute the given values in above formula we get;

750 = y(y-5)                            ......[1]

or we can write this as;

750 -y(y-5)=0

[1] ⇒y(y-5) =750  or

y^2-5y =750 or

y^2-5y-750=0

y^2-25y+30y-750=0

(y+25)(y-30)=0

Therefore, the equation which can be used to solve for y are;

y^2-5y =750 , 750 -y(y-5)=0  and (y+25)(y-30)=0




7 0
3 years ago
Read 2 more answers
PLZ HELP ASAP I FORGOT THE STEPS MY TEACHER TOLD ME TO DO IT
pav-90 [236]

1. 18x+16 in

To find the perimeter of a rectangle you have to add all the side together. Two sides are 5x+2 in and two sides are 4x+6 in. 5x+2+5x+2+4x+6+4x+6=18x+16

Sorry I don't know how to do the others.

7 0
4 years ago
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