Question

The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room.

Answer 1

Answer:

Option B , C  and E are correct

$y^2-5y =750$

$750 -y(y-5)=0$

(y+25)(y-30)=0

Step-by-step explanation:

Given : Area of rectangular room is 750 square feet.

Width of the room is 5 feet less than the length of the room.

Let y be the length of the room

then,

As per the given condition

width of the room is: y-5

Area of rectangle is multiply the length by its width.

Area of rectangle = $length \times width$

Substitute the given values in above formula we get;

$750 = y(y-5)$                            ......[1]

or we can write this as;

750 -y(y-5)=0

[1] ⇒$y(y-5) =750$  or

$y^2-5y =750$ or

$y^2-5y-750=0$

$y^2-25y+30y-750=0$

(y+25)(y-30)=0

Therefore, the equation which can be used to solve for y are;

$y^2-5y =750$ , $750 -y(y-5)=0$  and (y+25)(y-30)=0

Answer 2

Hello,

A:False
B:True
C:True
D:False
E:True