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3 years ago

Write the standard form equation in vertex form. Classify the type of equation it is.

Mathematics

1 answer:

QveST [7]3 years ago

5 0

I rewrote it in vertex form (I think). I don't remember how to classify ellipses, circles, etc.. (It's been a long time since I've seen these).

The answer is in the red circle.

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WILL GIVE BRAINLIEST!!!!!!!!!!!!! Which of the following shows the length of the third side, in inches, of the triangle below?

Dmitriy789 [7]

By the Pythagorean theorem:

 $third \ side = \sqrt{74^2-24^2} = \sqrt{5476-576}= \sqrt{4900}=70 \ in$

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3 years ago

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If you have a 100 point test and you have a c, what grade will you have if u get a d if

JulsSmile [24]

Probably a C-, but it depends on how many other grades are in the gradebook and the exact percentage of your grade.

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3 years ago

Araceli uses 6.1 pints of blue paint and white paint to paint her bedroom walls. 3/5 of this amount is blue paint, and the rest

kramer

Answer:

2.44 pints of white

Step-by-step explanation:

blue=3/5

white=2/5

6.1*0.4=2.44

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3 years ago

Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

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3 years ago

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What is the volume of a sphere that has a 12m diameter?

lesya [120]

Volume of Sphere = (4/3)*(pi)*(r^3)

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3 years ago