Answer:
5. c = 8pi cm
6. c = 18pi ft
7. c = 8.6pi in
8. c = 11/2pi m
Step-by-step explanation:
The circumference of a circle can be easily found using the formula: c = 
d, where the diameter is d.
Now you just plug your numbers into the formula!
5. c = pi x d
c = 8pi cm
6. This one gives you the radius instead of the diameter. All you need to do now is to double the radius to find the diameter.
9 ft x 2 = 18 ft
Now, it follows the formula.
c = pi x d
c = 18pi ft
7. c = pi x d
c = 8.6pi in
8. c = pi x d
c = pi x 2(2 3/4m) - Note that this is a mixed fraction. To be able to multiply it, you need to convert it to an improper fraction.
c = pi x 2(11/4)
c = pi x 11/2
c = 11/2pi m
:)
Answer:
2.50 + 5B ≤ 21;
Step-by-step explanation:
Cost of eggs = $2.50
Cost of avocado = $5 (bag of 3)
Total budgeted amount = $21
Bags of avocado = B
Therefore :
(Cost of eggs + cost of avocado) ≤ total budgeted amount
($2.50 + $5(B)) ≤ 21
2.50 + 5B ≤ 21
5B ≤ 21 - 2.50
5B ≤ 18.50
B ≤ 18.50 / 5
B ≤ 3.7
Therefore the maximum number of bags can purchase is 3(whole number without exceeding $21)
She needs to sell around 397 more shirts.
Divide 700 by 20.5. This will give you the amount of shirts she has already raised with is 36 (more accurately 36 6/41). Next divide 8900 by 20.5. This is the amount of shirts she needs to sell in total, which is 434. Subtract these two values.
Step-by-step explanation:
Due to the time it took to solve this question, I had little time to type the answers fully
The answers are contained fully in the attachment I have uploaded.
A. H0: u1 = u2
H1: u1 not equal to u2
The t statistics was solved to be 3.03
The degree of freedom was solved to be 26
Given this information, this is a 3 tailed test, critical value at 5% = +-2.056
T stat > critical value
We therefore reject the null hypothesis at 5% and conclude they have different mean wear
The p value is calculated using excel and the result is 0.00544
We reject null at 5% since p value is less than 0.05
B. H0: u1 = u2
H1: u1>u2
Alpha = 0.05
Following a,
Test stat = 3.03
Df = 26
Critical value for 1 tailed test = 1.706
Test stat > 1.706
We reject H0 and conclude company 1 has higher mean wear.
We find p value for a right tailed distribution using excel
Tdist(3.03,26,1)
= 0.002722
We reject h0
C. Confidence interval
1.610 < u < 8.390
Answer:
Lins house is 315 metres from school
Step-by-step explanation:
It's simple, just do 450-135.
