5 would have to be the constant, because in algebraic terms, a constant is a term that contains only numbers and no variables, which would knock 2x right out of the question. Hope I helped.
Answer:
9
Step-by-step explanation:
✯Hello✯
↪ There is a quadratic formula that needs to be used. 4ac and b^2 are a part of this formula
↪ First we need to work out the Values for A and B and C
A = 1
B = 5
C= 4
↪ now we can substitute this into what the equation is asking. (5)^2-4(1)(4)=9
↪ The answer is 9
↪ I hope this helps you :)
❤Gianna❤
Answer:
(-3,7)
Step-by-step explanation:
Step-by-step explanation:
x² + 20 = 2x
x² − 2x + 20 = 0
x = [ -b ± √(b² − 4ac) ] / 2a
x = [ -(-2) ± √((-2)² − 4(1)(20)) ] / 2(1)
x = [ 2 ± √(4 − 80) ] / 2
x = [ 2 ± √(-76) ] / 2
x = [ 2 ± 2i√19 ] / 2
x = 1 ± i√19
I believe the answer is 80 out of the 200 pay less than $5
hope this helps somehow
