Polynomial with real coefficients always has even number of complex roots. We know that one of them is 2 + 5i so the second one will be 2 - 5i and:

Answer B.
AB = 9 cm
BC = 6cm
CD = 7 cm
AE = 6 cm
3BC = AB
3ED = AE
AB = AE
BC ED
⁹/₃ = ⁶/ₓ
3 · 6 = 9 · x
18 = 9x
9 9
2 = x
ED = 2 cm
Answer:
$1.25.
Step-by-step explanation:
Since a product in maths means the result after multiplying numbers, you need to multiply 2 prime numbers and get 4.
If we look at the prime numbers: 2, 3, 5, 7, 11, etc, we see that the only number we can multiply to get 4 is 2, or, in other words, the only multiplication of prime numbers we can do to get four is 2*2=4.
Answer:
Step-by-step explanation:
300(3) + 40(3)+ 9(3)
600+120+27
747
700+40+7
not quite sure what answer you are looking for here