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olga2289 [7]
4 years ago
11

Question is in attachment. please answer quickly.

Mathematics
1 answer:
galina1969 [7]4 years ago
4 0

Answer:

Ques 4) option: B

Ques 5) option:C

Ques 6) option:C

Ques 7) option:B


Step-by-step explanation:

Ques 4)

The range of a function is the resulting y-values we get after substituting all the possible x-values.

Clearly from the figure we could see that the range of the function is:

-5<y<-2

the points -5 and -2 are not included as in the graph they are represented by a open circle.

Hence, option (b) is correct.

Ques 5)

Equation y=0.9x-45 represents the relationship.

from the table when we substitute x=50 then we get y=$0 only in the equation  y=0.9x-45.

Hence, option C is correct.

Ques 6)

The rate of change means the slope of the equation.

Let y denotes the total cost of bike.

Let x denotes the number of hours bike has been rented so in equation form the total cost is given by:

y=8x+15 (As it was given that bike cost $15 plus $8 for per hour)-----(1)

Let y' denote the total cost of scooter.

Let x' denotes the number of hours scooter has been rented.

Hence, the total cost is given by:

y'=5x'+35 ( as it was given scooter cost $35 plus $5 per hour)----(2)

The slope for equation (1) is 8 (since on comparing with the slope-intercept form y=mx+c where m denotes the slope and c denotes the y-intercept)

The slope for equation (2) is 5.

The bike rental has a rate of change 8 which is greater than the rate of change of scooter rental.

Hence, option: C is correct.

Ques 7)

We are given:

f(2)=\dfrac{1}{5}

and the recurrence relation is given as:

f(n+1)=f(n).10

hence, f(3)=f(2)×10=(1/5)×10=2

f(4)=f(3)×10=2×10=20

Hence, f(4)=20.

Hence, option B is correct.




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In the expansion of (1/ax +2ax^2)^5 the coefficient of x is five. Find the value of the constant a.
DedPeter [7]

Answer:

80x⁴

Step-by-step explanation:

(\frac{1}{ax} + 2ax^2)^5 = 5C_0(\frac{1}{ax})^5(2ax^2)^0 + 5C_1(\frac{1}{ax})^4(2ax^2)^1 + 5C_2(\frac{1}{ax})^3 (2ax^2)^2

                           + 5C_3 (\frac{1}{ax})^2(2ax^2)^3 + 5C_4(\frac{1}{ax})^1(2ax^2)^4 + 5C_5(\frac{1}{ax})^0(2ax^2)^5

5C_0(\frac{1}{ax})^5(2ax^2)^0  =1 \times (\frac{1}{ax})^5 \times 1 = \frac{1}{a^5x^5}\\\\5C_1(\frac{1}{ax})^4(2ax^2)^1  = 5 \times (\frac{1}{ax})^4 \times (2ax^2)^1 = 10 ax^2 \times \frac{1}{a^4x^4} = \frac{10}{a^3x^2}\\\\5C_2 (\frac{1}{ax})^3 (2ax^2)^2= 10 \times (\frac{1}{ax})^3 \times (2ax^2)^2 = 10 \times \frac{1}{a^3x^3} \times 4a^2x^4 = \frac{40x}{a}\\\\5C_3 (\frac{1}{ax})^2 (2ax^2)^3 = 10 \times (\frac{1}{ax})^2 \times (2ax^2)^3 = 10 \times \frac{1}{a^2x^2} \times 8a^3 x^6 = 80ax^4\\\\

5C_4(\frac{1}{ax})^1(2ax^2)^4 = 5 \times \frac{1}{ax} \times 16a^4x^8 = 80a^3x^7\\\\5C_5(\frac{1}{ax})^0(2ax^2)^5 = 1 \times 1 \times 32a^5x^{10}

The fourth term of the expansion has the constant a,

the coefficient of a is 80x⁴

6 0
3 years ago
A rocket is launched at t = 0 seconds. Its height, in meters above sea-level, is given by the equation
gogolik [260]

Answer:

Step-by-step explanation:

In order to find out how long it takes for the rocket to hit the ground, we only need set that position equation equal to 0 (that's how high something is off the ground when it is sitting ON the ground) and factor to solve for t:

0=-4.9t^2+112t+395

Factor that however you are factoring in class to get

t = -3.1 seconds and t = 25.9 seconds.

Since time can NEVER be negative, it takes the rocket approximately 26 seconds to hit the ground.

8 0
3 years ago
How do you do this problem?
schepotkina [342]

check the picture below.


GH = -6 + 2(8) = 10.

6 0
3 years ago
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allochka39001 [22]

Answer:

(Unless I am understanding the question/lesson wrong I know how to do this)

Step-by-step explanation:

On the first set you can see that 1 is the time and 3 is the distance so you would go to the chart and where it says time you would go right one time and I think since it says distance you would be the point up 3 times to the chart would look like (1,3).

Hope this helps :)

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3 years ago
Write the number 254 as a sum of hundreds,tens,and ones
Aloiza [94]
200+50+4=254 is the answer
5 0
3 years ago
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