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SOVA2 [1]
4 years ago
8

Compute 4567 ∙ 7890 ∙ 3^8 + 3579 ≡ ______ (mod 31)

Mathematics
1 answer:
Taya2010 [7]4 years ago
5 0

Answer: Our required value is 21.

Step-by-step explanation:

Since we have given that

4567.7890.3^8+3579(mod\ 31)

Now,

4567(mod\ 31)=10\\\\7890(mod\ 31)=16\\\\3^8(mod\ 31)=20\\\\3579(mod\ 31)=14

So, it becomes,

(10\times 16\times 20+14)(mod\ 31)\\\\=3214(mod\ 31)\\\\=21

Hence, our required value is 21.

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Julia and Cody are working together on solving math problems. For every one problem that Julia
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Answer:

Cody has solved (12 × 12) = 144 problems.

Step-by-step explanation:

For every one problem that Julia completes, Cody completes twelve.

If Julia Completes x problems and Cody completes y problems, then we can write y = 12x ........ (1)

Now, given that the number of problems solved by Cody is one hundred twenty more than two times the number of problems solved by Julia.

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Now, from equations (1) and (2) we get,  

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⇒ x = 12

Therefore, Cody has solved (12 × 12) = 144 problems. (Answer)

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