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natka813 [3]
3 years ago
6

Someone pls help! write the expression in radical form. 2 4/5

Mathematics
1 answer:
kipiarov [429]3 years ago
7 0

Answer:

  \sqrt[5]{2^4}

Step-by-step explanation:

Maybe you want 2^(4/5) in radical form.

The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.

  2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}

__

In many cases, it is preferred to keep the power inside the radical symbol.

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A community center rents their hall for special events. They charge a fixed fee of $200 plus an hourly fee of $22.50. Lin has $3
Karo-lina-s [1.5K]

Answer:

No, 6 hours would cost $335, 35 over her limit of $300.

Step-by-step explanation:

she has to pay $200 plus 22.50 for every hour she rents. So, if she rents for 6 hours, she has to pay $200 + 6(22.50) or $200 + 135=335. She only has $300 so she can’t afford the event.

3 0
2 years ago
Does the point (7 5) satisfy the equation y = x + -2
masha68 [24]

Answer:

Yes

Step-by-step explanation:

7 = x

5 = y

5 = X + - 2

5 = X - 2

If X is 7 then

5 = 7-2

5=5

yes

3 0
3 years ago
Multiplication Property of Equality---- If 6x divided by 8 = 40, then______
NNADVOKAT [17]

Answer:

Option C.) 6x=320

Step-by-step explanation:

we know that

The <u>Multiplication Property of Equality</u> states that if you multiply both sides of an equation by the same number, the sides remain equal

we have

\frac{6x}{8}=40

Apply the multiplication property of equality

Multiply by 8 both sides

\frac{6x}{8}(8)=40(8)

6x=320

therefore

The answer is the Option C

6 0
3 years ago
Read 2 more answers
Someone please help! No link answer please :(
grandymaker [24]

Answer:

55 degrees (a)

Step-by-step explanation:

complementary means they equal 90 degrees

so 90-35= 55 degrees

3 0
3 years ago
What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove
wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

  • \frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2

5b^3-10=6b^3-4b^2-10

\mathrm{Switch\:sides}

6b^3-4b^2-10=5b^3-10

6b^3-4b^2-10+10=5b^3-10+10

6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

b^3-4b^2=0

Using\:the\:Zero\:Factor\:Principle: if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

b=0,b-4=0

b=0,b=4

Therefore, the solutions are:

b=0,\:b=4

4 0
3 years ago
Read 2 more answers
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