Long division: (x³ + 2) ÷ (x + 1)
<u> </u><u>x² – x + 1 </u>
x³ + 0x² + 0x + 2 | x + 1
<u>– x³ – x²</u> ⋮ ⋮
– x² + 0x ⋮
<u>+ x² + x</u><span> ⋮</span>
+ x + 2
<span> </span> <u>– x – 1</u>
+ 1
Quotient: Q(x) = x² – x – 1;
Remainder: R(x) = + 1.
I hope this helps. =)
x(x-7)=8
x^2-7x-8=0
(x-8)(x+1)=0
so x=8 (and -1 but width can’t be negative)
So your answer is C. 8
Answer:
No.
Step-by-step explanation:
It has different order of matrices .
For <em>A</em><em>d</em><em>d</em><em>i</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>or <em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>r</em><em>a</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>, both matrices must have the same number of <u>r</u><u>o</u><u>w</u><u>s</u> and <u>c</u><u>o</u><u>l</u><u>u</u><u>m</u><u>n</u><u>s</u> .
<span>2x-y = 7 so y = 2x - 7
y = 2x+3
2x - 7 = 2x + 3
0 = 10
Answer
No solution</span>
Answer:
14
4
8
Step-by-step explanation:
