Answer:
Percentage of mass of solute in aqueous phase is 28.57%.
Explanation:
- Fraction of solute in aqueous phase.

= Used volume of aqueous solution
= Used volume of organic solution
D = partition coefficient.

Mass of solute in aqueous phase = 

Therefore, Percentage of mass of solute in aqueous phase is 28.57%.
Answer:
D
Explanation: A precipitation reaction is a type of chemical reaction in which two soluble salts in aqueous solution combine and one of the products is an insoluble salt called a precipitate.
Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
Explanation:
Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L
Molarity = 0.750 M
It is known that molarity is the number of moles of solute present in liter of a solution.
Therefore, moles present in given solution are calculated as follows.

Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.