Calculate the number of joules released when 72.5 grams of water at 95 degrees Celsius to a final temperature of 28 degrees Cels
1 answer:
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Answer : The amount of oxygen gas collected are, 0.217 mol
Explanation :
Using ideal gas equation :
where,
P = pressure of gas = (1 atm = 760 torr)
V = volume of gas = 5 L
T = temperature of gas =
n = number of moles of gas = ?
R = gas constant = 0.0821 L.atm/mol.K
Now put all the given values in the ideal gas equation, we get:
Thus, the amount of oxygen gas collected are, 0.217 mol
Answer:
Kp = 0.81666
Explanation:
Pressure of PCl₅ = 0.500 atm
Considering the ICE table for the equilibrium as:
PCl₅ (g) ⇔ PCl₃ (g) + Cl₂ (g)
t = o 0.500
t = eq -x x x
--------------------------------------------- --------------------------
Moles at eq: 0.500-x x x
Given the pressure of PCl₅ at equilibrium = 0.150 atm
Thus, 0.500 - x = 0.150
x = 0.350 atm
The expression for the equilibrium constant is:
So,
x = 0.350 atm
Thus,
<u>Thus, Kp = 0.81666</u>
Answer:
Both are pure substances and a compound
