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Oxana [17]
3 years ago
9

For each given p, let ???? have a binomial distribution with parameters p and ????. Suppose that ???? is itself binomially distr

ibuted with parameters ???? and ????. Formulate ???? as a random sum and show that ???? has a binomial distribution with parameters p???? and ????.
Mathematics
1 answer:
pshichka [43]3 years ago
8 0

Answer:

See the proof below.

Step-by-step explanation:

Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."

Solution to the problem

For this case we can assume that we have N independent variables X_i with the following distribution:

X_i Bin (1,p) = Be(p) bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:

Z = \sum_{i=1}^N X_i

From the info given we know that N \sim Bin (M,q)

We need to proof that Z \sim Bin (M, pq) by the definition of binomial random variable then we need to show that:

E(Z) = Mpq

Var (Z) = Mpq(1-pq)

The deduction is based on the definition of independent random variables, we can do this:

E(Z) = E(N) E(X) = Mq (p)= Mpq

And for the variance of Z we can do this:

Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2

Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2

And if we take common factor Mpq we got:

Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]

And as we can see then we can conclude that   Z \sim Bin (M, pq)

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leonid [27]

The answer is the square root of 324



4 0
2 years ago
I’ve been stuck on this for a while now and i can’t get passed it can someone please help me out please please help
KonstantinChe [14]

Answer:

(D.) $5.35

Step-by-step explanation:

1.25+0.35=1.60

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4 0
2 years ago
Find all the missing sides and angles of this triangle.
3241004551 [841]

Answer:

A = 20°

AC = 6.6

BC = 2.4

Step-by-step explanation:

Given:

B = 70°

C = right angle = 90°

AB = 7

Required:

A, AC, and BC

Solution:

✔️A = 180 - (90 + 70) (sum of triangle)

A = 20°

✔️Use trigonometric function to find AC:

Refernce angle = 70°

Opp = AC

Hypotenuse = 7

Apply SOH,

sin 70 = Opp/Hyp

sin 70 = AC/7

7 * sin 70 = AC

6.57784835 = AC

AC = 6.6 (nearest tenth)

✔️Use trigonometric function to find Bc:

Refernce angle = 70°

Adj = BC

Hypotenuse = 7

Apply CAH,

cos 70 = Adj/Hyp

cos 70 = BC/7

7 * cos 70 = BC

2.394141 = BC

BC = 2.4 (nearest tenth)

3 0
3 years ago
What is 1 1/4 + -3 5/6
julia-pushkina [17]

Answer:

-2\frac{7}{12}

Step-by-step explanation:

Convert the mixed numbers to improper fractions, then find the LCD and combine and getting you -2 7/12

<u>Hopes this helps</u>

4 0
3 years ago
A wire that is 22 feet long connects the top of a pole to the ground. The wire is attached to the ground at a point that is 10 f
krok68 [10]

✰ <u>Concept</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>

⠀

In this question, we can clearly observer that the diagram shows a right angled triangle. And, we have been provided with the value of base, and the value of hypotenuse, using the pythagoras theorem, now we can easily find out the value of the perpendicular i.e. the value of the side h. According to the pythagoras theorem, square of hypotenuse is equal to the sum of square of perpendicular and square of side respectively. Therefore, square of side is equal to the difference of square of hypotenuse and square of perpendicular.

⠀

✰ <u>Given</u><u> </u><u>Information</u><u> </u>:-

⠀

  • Hypotenuse = 22 ft.
  • Base = 10 ft.

⠀

✰ <u>To Find</u><u> </u><u>:</u><u>-</u>

⠀

  • The value of side or the perpendicular

⠀

✰ <u>Formula</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>

⠀

\star \:  \underline{ \boxed{ \purple { \sf  {Side}^{2}  =  {Hypotenuse}^{2}  -  {Base}^{2}  }}} \:  \star

⠀

✰ <u>Solution</u><u> </u><u>:</u><u>-</u>

⠀

\sf \longrightarrow  {Side}^{2} =   {(22 \: ft)}^{2}  -  {(10 \: ft)}^{2}  \:  \:  \:  \\  \\  \\ \sf \longrightarrow  {Side}^{2} =   {484 \: ft}^{2}  -  {100 \: ft}^{2}  \:  \:  \: \:  \:  \:   \\  \\  \\ \sf \longrightarrow  {Side}^{2} =   {384 \: ft}^{2}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \\ \sf \longrightarrow  {Side}^{} =   \sqrt{ {384 \: ft}^{2} }  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \\ \sf \longrightarrow  {Side}^{} =   \underline{ \boxed{ \frak{ \green{19.60 \: ft}}}} \:  \star \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\

Thus, option B. 19.60 ft. is the correct option.

⠀

\underline{\rule{230pt}{2pt}} \\  \\

4 0
2 years ago
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