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Zielflug [23.3K]
3 years ago
8

PLS help me ASAP i will give thanks and 5 stars and please make sure to show your work

Mathematics
1 answer:
krek1111 [17]3 years ago
5 0

Answer:

2. 4.57÷3=1.523

3. 6.45÷5=1.29

7. 80÷1.5=53.3

8. 46.483÷0.2=232.415

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1. The temperature was -8°F and rose by 2°F. What is the new temperature? Expression:​
aev [14]
New temperature: -6°
-8 +2= -6
3 0
2 years ago
Simplify the expression
lapo4ka [179]
What expression? I don't see any

3 0
3 years ago
Hi guys please help meee
Lisa [10]
<h3>Answer: 10</h3>

=======================================================

Explanation:

We'll start off converting each mixed number into an improper fraction.

The formula to use is A \frac{b}{c} = \frac{A*c+b}{c}

So,

A \frac{b}{c} = \frac{A*c+b}{c}\\\\2 \frac{1}{8} = \frac{2*8+1}{8}\\\\2 \frac{1}{8} = \frac{16+1}{8}\\\\2 \frac{1}{8} = \frac{17}{8}\\\\

And,

A \frac{b}{c} = \frac{A*c+b}{c}\\\\2 \frac{2}{3} = \frac{2*3+2}{3}\\\\2 \frac{2}{3} = \frac{6+2}{3}\\\\2 \frac{2}{3} = \frac{8}{3}\\\\

So the task of computing 2 \frac{1}{8} \times 2 \frac{2}{3} is exactly the same as computing \frac{17}{8} \times \frac{8}{3}

Notice how we have an 8 up top and an 8 down below. Those 8's cancel out and we're left with \frac{17}{3}. That fraction does not reduce any further.

The last step is to convert that improper fraction result to a mixed number.

\frac{17}{3} = \frac{15+2}{3}\\\\\frac{17}{3} = \frac{15}{3}+\frac{2}{3}\\\\\frac{17}{3} = 5+\frac{2}{3}\\\\\frac{17}{3} = 5 \frac{2}{3}\\\\

Or you could note that 17/3 leads to 5 remainder 2. The 5 is the whole part and the 2 forms the numerator of the fractional part 2/3.

The value is in A \frac{b}{c} form where

  • A = 5
  • b = 2
  • c = 3

Therefore, A+b+c = 5+2+3 = 10

8 0
2 years ago
Read 2 more answers
Select the correct answer. What is the range of the function f(x) = 3x − 12 for the domain {-2, 2}? A. {3, 12} B. {-6, -18} C. {
stellarik [79]

Answer:answer of questions get B

,,, just x is between two numbers after that create the function (-6,-18)

6 0
3 years ago
-------100 POINTS------<br> Complete the proof of the Pythagorean theorem.
KIM [24]

Step-by-step explanation:

Complete the proof of the Pythagorean theorem is given below.

         Statement                                              Reason

1. ΔABC is a right triangle, with a     1. Given

right angle at ∠C

2. Draw an altitude from point C     2. From a point not on a line, exactly                    

to AB               one perpendicular can be drawn through the point to the line

3. ∠CDB and ∠CDA are right          3. Definition of altitude

angles

4. ∠BCA  ≅ ∠BDC                            4. All right angles are congruent

5. ∠B  ≅ ∠B                                      5. Reflexive\:Property

6. ΔCBA ~ ΔDBC                             6. AA Similarity Postulate                                                                                                                                                                                                                                      

7. \frac{a}{x}\:=\:\frac{c}{a}                                           7. Polygon\:Similarity\:Postulate\:\:\:

8. a^{2}  = cx                                          8. Cross\:Multiply\:and\:Simplify

9. ∠CDA  ≅ ∠BCA                           9. All\:Right\:Angles\:are\:Congruent

10. ∠A  ≅ ∠A                                    10. Reflexive\:Property

11. ΔCBA ~ ΔDBA                             11. AA Similarity Postulate

12. \frac{b}{y}\:=\:\frac{c}{b}=                                      12. Polygon\:Similarity\:Postulate

13. b^2\:=\:cy                                       13. Cross\:Multiply\:and\:Simplify

14. a^2\:+\:b^2\:=\:cx\:+cy                    14. Addition\:Property\:of\:Equality

15. \left(CB\right)^2+\left(CA\right)^2=\left(AB\right)\left(DB+BA\right)  15. Distributive Property

16. x + y = c                                    16. Segment\:Addition\:Postulate

17. a^2\:+\:b^2\:=\:c^2                             18. Substitution\:Property

7 0
3 years ago
Read 2 more answers
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