Has to multiply I think try that !
First factor the numerator
b^2-6b+8/b-4 * b+8/b-2
u will get
(b-2)(b-4)/(b-4)*(b-2)*b+8
those will cancel out each other will left only
b+8<span />
Answer:A
Step-by-step explanation:
False. When a quadrilateral has two sets of parallel sides ,like I drew below, all four corners form right angles.