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lisabon 2012 [21]
3 years ago
12

What is the place value of 8 in 0.829

Mathematics
2 answers:
VladimirAG [237]3 years ago
6 0
The 8 is in the tenths place, the 2 is in the hundredths place, and the 9 is in the thousandths place. Hope this helps, please mark brainliest Have a great night.
KengaRu [80]3 years ago
3 0
The answer is the tenths place
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List these from least to greatest π2, 12, √80
Evgesh-ka [11]

Answer:

π2,√80,12

Step-by-step explanation:

π2= 6.28

√80= about 8

12=12

Hope I could help!

5 0
2 years ago
Sam buys 4 tropical fish. Each fish is 5/8 of an inch long. Write an equation that represents 4 x 5/8 as a multiple of a unit fr
UkoKoshka [18]
4 x 5/8= 20/8= 10/4=5/2 inches lng
3 0
3 years ago
{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
3 years ago
Consider the isosceles triangle. left side (2x+8)units bottom of triangle (4x-10)units right side of triangle (2x+8) units Part
Blizzard [7]

Complete Question

Consider the isosceles triangle. left side (2z+8)units, bottom of triangle (4z-10)units, right side of triangle (2z+8) units Part A Which expression represents the perimeter of the triangle? a.(4z+16) units b.(6z−2)units c.(8z−16) units d.(8z+6) units

Answer:

d. (8z + 6) units

Step-by-step explanation:

The formula for the Perimeter of a Triangle is :Side A + Side B + Side C

Hence,

(2z + 8)units + (4z - 10) units + (2z + 8)units

= (2z + 8 + 4z - 10 + 2z + 8)units

Collect like terms

= 2z + 4z + 2z + 8 - 10 + 8

= 8z + 6 units

The expression that represents the perimeter of the triangle is (8z +6) units

3 0
3 years ago
HELLPP!!!!!!!!!!!!!!!!!!!!!!!!!
Genrish500 [490]

\left\{\begin{array}{ccc}2x-3y=-27&|\cdot3\\-3x+2y=23&|\cdot2\end{array}\right\\\underline{\left\{\begin{array}{ccc}6x-9y=-81\\-6x+4y=46\end{array}\right}\ \ \ \ |\text{add both sides}\\.\ \ \ \ \ \ -5y=-35\ \ \ \ \ |:(-5)\\.\ \ \ \ \ \ \ \ y=7\\\\\text{put the value of y to the first equation}\\\\2x-3(7)=-27\\\\2x-21=-27\ \ \ \ |+21\\\\2x=-6\ \ \ \ |:2\\\\x=-3\\\\\text{Answer:}\ x=-3,\ y=7\to\boxed{(-3,\ 7)}

6 0
3 years ago
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