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egoroff_w [7]
2 years ago
8

Am I correct? If so why?

Mathematics
1 answer:
babunello [35]2 years ago
7 0

Answer: its correct

Step-by-step explanation: and its correct cuase its the answer you choose

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Find x so that q || r Please help
sweet-ann [11.9K]

Answer:

7 and the corresponding angle theorem

Step-by-step explanation:

6 0
3 years ago
20 units Humulin R insulin in 100 mL of normal saline (NS) to infuse for 20 hours. (Round to the nearest tenth if applicable) a.
wariber [46]

Answer:

a) 1 unit per hour will be infused.

b) 5mL per hour will be infused.

Step-by-step explanation:

Each question can be solved as a rule of three with direct measures, that means we have a cross multiplication.

a. How many units per hour will be infused?

20 units are going to be infused in 20 hours. How many units are going to be infused each hour?

1 hour - x units

20 hours - 20 units

20x = 20

x = \frac{20}{20}

x = 1

1 unit per hour will be infused.

b. How many milliliters per hour will be infused?

100mL are going to be infused in 20 hours. How many mL are going to be infused each hour?

1 hour - x mL

20 hours - 100 mL

20x = 100

x = \frac{100}{20}

x = 5

5mL per hour will be infused.

4 0
3 years ago
A group of students were asked if they are in the Math Club and if they are in ti
qwelly [4]

Answer: 22

Step-by-step explanation:

6 0
2 years ago
In one area, monthly incomes of technology-related workers have a standard deviation of $650. It is believed that the standard d
Virty [35]

Answer:

There is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.

Step-by-step explanation:

Here we have our null hypothesis as H₀: σ² = s²

Our alternative hypothesis is then Hₐ: σ² ≠ s²

We therefore have a two tailed test

To test the hypothesis of difference in standard deviation which is the Chi squared test given as follows

\chi ^{2} = \dfrac{\left (n-1  \right )s^{2}}{\sigma ^{2}}

Where:

n = Size of sample

s² = Variance of sample = 950²

σ² = Variance of population = 650²

Degrees of freedom = n - 1 = 71 - 1 = 70

α = Significance level = 0.1

Therefore, we use 1 - 0.1 = 0.9

From the Chi-square table, we have the critical value as

1 - α/2 = 51.739,  

α/2 = 90.531

Plugging the values in the above Chi squared test equation, we have;

\chi ^{2} = \dfrac{\left (23-1  \right )950^{2}}{650 ^{2}} = 49.994

Therefore, since the test value within the critical region, we do not reject the null hypothesis, hence there is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.

6 0
2 years ago
Someone please help me
Mazyrski [523]
64 percent is your answer

3 0
3 years ago
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