20y+30x=1000 divide 20 on each side to st the y alone.
y+30x=50 next put it in slope intercept form
y=30x+50 I don't know if this was te answer you were looking for but I hope it is
Given:
Consider the equation is:
To prove:
by using the properties of logarithms.
Solution:
We have,
Taking left hand side (LHS), we get
![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)
![[\because \log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%20x%5En%3Dn%5Clog%20x%5D)
Hence proved.
There would be 2 groups. The greatest amount in each pile is 2 cards.
Answer:
Consider the following system of equations given in slope-intercept form.
y = −1
3
x + 17,
y = 5x - 23
Step-by-step explanation:
Answer:
n < 27
Step-by-step explanation:
let the number be n
