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3 years ago

Find the sum of 2y²+3yz-y²-yz-z²+6zy-3y² please help STEP explanation

Mathematics

2 answers:

larisa86 [58]3 years ago

7 0

Answer:

See picture attached

Step-by-step explanation:

I hope this helps you.

Please give me brainliest if it's correct

kozerog [31]3 years ago

5 0

=2y^2 - 3y^2 - y^2 + 3yz - yz - z^2 + 6zy ( arranging the like terms )

= -2y^2 + 2yz - z^2 + 6z ( simpliflying the like terms and leaving the unlike terms same as it is rule )

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in a class of 32 students the mean height of the 14 boys is 1.56 meters and the mean height of all 32 students is 1.151 meters.

Nimfa-mama [501]

Answer: Hence, Mean height of the girls is: 1.48

Step-by-step explanation: It is given that:

in a class of 32 students .

the mean height of 14 boys is 1.56 and the mean height of all 32 students is 1.515.

Since there are 14 boys in a class.

So, number of girls is equal to (32-14)=18.

The mean height of 14 boys is 1.56.

Hence the sum of height of 14 boys is= 1.56×14=21.84

Similarly mean height of 32 students is 1.515.

Hence, sum of height of 32 students=1.515×32=48.48.

Let x denote the mean height of 18 girls.

Hence, sum of height of 18 girls is: 18 x.

Now,

18x+21.84=48.48

( since sum of height of girls and boys is equal to the sum of height of all the students)

so, 18x=48.48-21.84

18 x=26.64

Hence, x=1.48

Hence, Mean height of the girls is: 1.48

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3 years ago

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garri49 [273]

Answer:

1.7

Step-by-step explanation:

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3 years ago

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blondinia [14]

Xm=(2+2)/2=2 Ym=(1+4)/2=2.5 (2,2.5)

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3 years ago

Pears are $1.98 a pounds. How much do 3.5 pounds of Pears cost?

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3 years ago

John, sally, Natalie would all like to save some money. John decides that it would be best to save money in a jar in his closet

stiv31 [10]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) $y=100x+300$

Part 3) $\$12,300$

Part 4) $\$2,700$

Part 5) Is a exponential growth function

Part 6) $A=6,000(1.07)^{t}$

Part 7) $\$11,802.91$

Part 8) $\$6,869.40$

Part 9) Is a exponential growth function

Part 10) $A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

Part 11) $\$13,591.41$

Part 12) $\$6,107.01$

Part 13) Natalie has the most money after 10 years

Part 14) Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

$y=mx+b$

The slope is equal to

$m=\$100\ per\ month$

The y-intercept or initial value is

$b=\$300$

$y=100x+300$

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

$y=100x+300$

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

$10\ years=10(12)=120 months$

For x=120 months

substitute in the linear equation

$y=100(120)+300=\$12,300$

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

$2\ years=2(12)=24\ months$

For x=24 months

substitute in the linear equation

$y=100(24)+300=\$2,700$

Part 5) What type of exponential model is Sally’s situation?

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$P=\$6,000\\ r=7\%=0.07\\n=1$

substitute in the formula above

$A=6,000(1+\frac{0.07}{1})^{1*t}\\ A=6,000(1.07)^{t}$

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

$A=6,000(1.07)^{t}$

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{10}=\$11,802.91$

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{2}=\$6,869.40$

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$P=\$5,000\\r=10\%=0.10$

substitute in the formula above

$A=5,000(e)^{0.10t}$

Applying property of exponents

$A=5,000(1.1052)^{t}$

therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

$A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

$A=5,000(e)^{0.10*10}=\$13,591.41$

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

$A=5,000(e)^{0.10*2}=\$6,107.01$

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

3 0

3 years ago

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Find the sum of 2y²+3yz-y²-yz-z²+6zy-3y² please help STEP explanation ​

Find the sum of 2y²+3yz-y²-yz-z²+6zy-3y² please help STEP explanation