Question

What is the cube root of 27a12

Answer 1

Answer:

$3a^4$

Step-by-step explanation:

Given expression is $27a^{12}$.

Now we need to find the cube root of given expression $27a^{12}$.

$\sqrt[3]{27a^{12}}$

$=\sqrt[3]{3*3*3a^{4*3}}$

$=\sqrt[3]{3^3\left(a^4\right)^3}$

$=\sqrt[3]{\left(3a^4\right)^3}$

Since cube root and cube are opposite operations of each other. So they will cancel each other.

$=3a^4$

Hence correct choice is the last choice $3a^4$.