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sineoko [7]
3 years ago
5

A researcher wondered whether drivers treat bicycle riders differently when they wear helmets. He rigged his bicycle with an ult

rasonic sensor that could measure how close each car was that passed him. He then rode on alternating days with and without a helmet. Of the 30003000 times that a car passed​ him, he found that when he wore his​ helmet, motorists passed 3.273.27 inches closer to​ him, on​ average, than when his head was bare. What is the WhoWho in this​ study? That​ is, identify the cases under study.
A. The bike riders
B. Each instance of a car passing a rider
C. Bike helmets
D. The cars
Mathematics
1 answer:
andrew-mc [135]3 years ago
3 0

Answer:

In this case study we have following groups:

1. Population: It had all the cars which passed the bicyclist. Out of which 3000 cars were taken.

2. Who:  Each instance of a car passing a rider, means the drivers passing by.

That is the 3000 cars which passed the researcher on his bicycle.

3. What: The distance at which cars pass the bicycle rider. The distance the drivers stayed away from his bike.

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Which is the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively?
WARRIOR [948]

Answer:

Which is the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively? 204.

Step-by-step explanation:

Have a great summer.

8 0
3 years ago
Read 2 more answers
The sum of three consecutive integers is greater than 66. What is the smallest possible product of the largest and smallest of t
AysviL [449]

Answer:

528

Step-by-step explanation:

So naturally at first sight for this question we would think -->

Oh 3 consecutive integers = 66 --> 66/3 = 22 (n-1), (n+1) so --> 21, 22, and 23.

But no. At second look it is the sum of 3 consecutive integers is greater than 66. So we find the next possible pair since it says smallest possible product.

We get the set (22, 23, 24). => Multiply the least and greatest integers together respectively 22 and 24 which amounts to => 528

And thus, we have out answer of 528

Hope this helps!

4 0
3 years ago
Select ALL the correct answers.
Marina CMI [18]

Answer:

The median of A is the same as the median of B.

The interquartile range of B is greater than the interquartile range of A.

Step-by-step explanation:

Given that:

A = number of runs allowed in first 9 games

A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

Rearranging A : 1, 1, 1, 1, 2, 2, 2, 3, 4

Median A = 1/2(n + 1) th term

Median A = 1/2(10) = 5th term = 2

Q1 of A = 1/4(10) = 2.5th term = (1 + 1)/ 2 = 1

Q3 of A = 3/4(10) = 7.5th term = (2+3)/2 = 2.5

Interquartile range = Q3 - Q1 = 2.5 - 1 = 1.5

Number of runs allowed in 10th game = 9

B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

Median A = 1/2(n + 1) th term

Median A = 1/2(11) = 5.5th term = (2+2)/2 = 2

Q1 of A = 1/4(11) = 2.75th tetm = (1 + 1)/ 2 = 1

Q3 of A = 3/4(11) = 8.25th term = (3+4)/2 = 3.5

Interquartile range = Q3 - Q1 = 3.5 - 1 = 2.5

Median A = 2 ; median B = 2

IQR B = 2.5 ; IQR A = 1.5 ; IQR B > IQR A

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2 years ago
Find the common difference for the given sequence.
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A car is traveling at a rate of 81 kilometers per hour. What is the cars rate in kilometers per minute. How many kilometers will
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