2 years ago

What is the area of a trapezoid ABCD with bases

Mathematics

1 answer:

zheka24 [161]2 years ago

6 0

A picture can help you sort this out.

Draw point E on CD so that AE ⊥ CD. Then the distance DE is 8cos(60°) = 4, and the height AE is 8sin(60°) = 4√3. The length of CD is 8+2×4 = 16. The area of the trapezoid is the product of the height and the average base length:

... A = (b1 +b2)/2×h = (8 cm + 16 cm)/2×(4√3 cm) = 48√3 cm² ≈ 83.14 cm²

You might be interested in

2 and 2 over 2, divided by -1/4 = what

alex41 [277]

Answer:

1.75

Step-by-step explanation:

it is right

6 0

2 years ago

How do I prove that a quadrilateral is a rectangle?

maw [93]

I think you want to prove that a rectangle is a quadrilateral. You can prove this with definitions. The definition of a quadrilateral is that it is a shape with four sides. Since a rectangle has four sides, that proves that a rectangle is a quadrilateral.

7 0

2 years ago

Read 2 more answers

A 20 foot ladder is leaning against the side of a building. The bottom of the ladder is 4 feet from the wall. How many feet abov

Semenov [28]

It form a right triangle
legnth of ladder is hypotonuse
bottom of ladder from wall distance is one leg
distance up wall is other leg
a^2+b^2=c^2
c=hypotonuse and a and b are legs

4^2+b^2=20^2
16+b^2=400
minus 16 both sides
b^2=384
sqrt both sides
b=8√6 ft
aprox
b=19.59ft from ground

6 0

3 years ago

Help me, cause I'm tuck

r-ruslan [8.4K]

Answer:

The answer would be 1.33 x $10^{4}$