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user100 [1]
3 years ago
8

Help asap!! interpret the meaning of the expression

Mathematics
2 answers:
Triss [41]3 years ago
4 0

Answer:

D

Step-by-step explanation:

This is exponential growth, and to my understanding, the format goes:

<em>initial amount (percent growth/ decay)^time</em>

percent growth = (<em>decimal percent + 1)</em>

<em>percent decay = (1 - decimal percent) </em>

Your equation:

1500(1.02)^t

Using the above format, 1500 appears to be the initial amount, which increases by 2% per annum.

i think

Lilit [14]3 years ago
3 0

Answer D

Step-by-step explanation:

FOR PLATO

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8 0
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A clothing store used the sign show below to advertise a discount on shirts:
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Tax= Tax %(Price of 2 Shirts + 50% of 3rd Shirt)
Tax= 7.1%[49.96+49.96+1/2(49.96)]
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7 0
3 years ago
Read 2 more answers
How much would $300 invested at 7% interest compounded continuously be worth after 4 years
marissa [1.9K]
The formula of compound continuously is
A=p e^rt
A future value?
P present value 300
R interest rate 0.07
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E constant
A=300×e^(0.07×4)
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8 0
3 years ago
In this exercise, T: R2 → R2 is a function. For each of the following parts, state why T is not linear. (a) T(a1, a2)= (1, a2) (
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Answer:

  • a) T is not homogeneous
  • b) T is not additive
  • c) T is not homogeneous
  • d) T is not additive
  • e) T is not additive

Step-by-step explanation:

In each case there is an example where one property of linear functions fails.

  • a) T(2(1,0))=T((2,0))=(1,0); 2T((1,0))=2(1,0)=(2,0). These vectors are not equal, then T doesn't satisfy the condition of scalar multiplication (homogeneity).
  • b) T((1,2)+(2,3))=T(3,5)=(3,9); T((1,2))+T((2,3))=(1,1)+(2,4)=(3,5). Because these vectors are not equal, T doesn't satisfy the property of vector addition (additivity).
  • c) T(\frac{1}{2}(\pi,0))=T((\frac{\pi}{2},0))=(\sin(\frac{\pi}{2}),0)=(1,0); \frac{1}{2}T((\pi,0))=\frac{1}{2}(0,0)=(0,0) so T is not homogeneous.
  • d) T((-1,0)+(1,0))=T(0,0)=(0,0); T((-1,0))+T((1,0))=(1,0)+(1,0)=(2,0) then T is not additive.
  • e) T((0,0)+(1,0))=T(1,0)=(2,0); T((0,0))+T((1,0))=(1,0)+(2,0)=(3,0) then T is not additive.
8 0
3 years ago
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