Answer:
a) what is the probability that Neither will of these products launch ?
= 0.30
b) At least one product will be launched ?
= 0.70
Step-by-step explanation:
From the above question, we have the following information:
P(A) = 0.45
P(B) = 0.60
P(A ∩ B) = P(A and B) launching = 0.35
Step 1
We find the Probability that A or B will launch
P (A ∪ B) = P(A) + P(B) - P(A ∩ B)
= 0.60 + 0.45 - 0.35
= 1.05 - 0.35
= 0.70
a) what is the probability that Neither will of these products launch ?
1 - Probability ( A or B will launch)
= 1 - 0.70
= 0.30
b)At least one product will be launched?
This is equivalent to the probability that A or B will be launched
P (A ∪ B) = P(A) + P(B) - P(A ∩ B)
= 0.60 + 0.45 - 0.35
= 1.05 - 0.35
= 0.70
It’s LM becuase look at the photo Lm means
Answer:
1.8m^2 approx
Step-by-step explanation:
Given data
P1= 1400N
A1=0.5m^2
P2=5000 N
A2=??
Let us apply the formula to calculate the Area A2
P1/A1= P2/A2
substitute
1400/0.5= 5000/A2
cross multiply
1400*A2= 5000*0.5
1400*A2= 2500
A2= 2500/1400
A2= 1.78
Hence the Area is 1.8m^2 approx
The common factors are 1 and 2.
Factors of 74.48:
1,2,37,74
Factors of 52.50:
1,2,4,13,26,52
Answer: <u><em>pls mark as brainliest</em></u>
2x+3y>-3
First we forget the inequality sign
2x+3y=-3
Then we solve for y
3y = -3-2x
3y=-2x-3
y=-\frac{2x}{3}-1
which is of the form y =mx +b
So here slope m is 2/3 and y intercept is -1 .
First we graph .
And then we have to check, which part need to be shaded . And for that , we take a testing point. Let it be (0,0) .
Now we plug this point in the given inequality that is 2(0)+3(0)>-3
0+0>-3
0>-3 which is true. SO we have to shade that part of the graph where point (0,0) belongs .
Step-by-step explanation: