Answer:
toooook teaehes
Step-by-step explanation:
sedmee endm the worlds nssssssssssssss
We are given: On january 1, 2000 initial population = 67,255.
Number of people increase each year = 2935 people.
Therefore, 67,255 would be fix value and 2935 is the rate at which population increase.
Let us assume there would be t number of years after year 2000 and population P after t years is taken by function P(t).
So, we can setup an equation as
Total population after t years = Number of t years * rate of increase of population + fix given population.
In terms of function it can be written as
P(t) = t * 2935 + 67255.
Therefore, final function would be
P(t) = 2935t +67255.
So, the correct option is d.P(t) = 67255 + 2935t.
Answer:
$1783.03
Step-by-step explanation:
Annually compounding interest formula:
PV(1+i)ⁿ
1500(1+.025)⁷
1500(1.025)⁷
1783.028631
which rounds to
1783.03
Since a log graph is with base 10 and a ln graph is with base e (2.something), the log x graph will clearly have smaller numbers (as, for example, log100=2 and ln100=around 4.6). In addition, you only have to multiply a number by e to increase the power by 1 but you have to multiply a number by 10 (which is significantly larger than e) to increase logx's power by 1, therefore proving that the log x graph will grow slower
