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3 years ago

14

Generate the first five terms in the sequence using explicit formula

1 answer:

ioda3 years ago

8 0

I got b i did this question before but dont take my word for it im not one hundred percent sure

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What is the value of x = ?

jeka57 [31]

I think it is 174. I could be wrong.

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3 years ago

Need help!! “Use the Pythagorean theorem to find the missing side of the right triangle.”

sasho [114]

Answer:

x=6

Step-by-step explanation:

a²+b²=c²

x²+8²=10²

x²+64=100

x²=36

x=6

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3 years ago

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3) A semicircle is attached to the side of a rectangle as shown.

m_a_m_a [10]

Rectangle = 18 x 6 = 108
Circle: 3.14 x (3)^2 = 3.14 x 9 = 28.26
<span>semicircle: 28.26 / 2 = 14.13
</span>
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answer
122.13 cm^2

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3 years ago

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How do I solve 8/x-0.16=0.64

Andreas93 [3]

Answer:

yo my bad

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3 years ago

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A group of three undergraduate and five graduate students are available to fill certain student government posts. If four studen

creativ13 [48]

Answer:

$Pr = 0.4286$

Step-by-step explanation:

Given

Let

$U \to\\$ Undergraduates

$G \to$ Graduates

So, we have:

$U = 3; G =5$ -- Total students

$r = 4$ --- students to select

Required

$P(U =2)$

From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.

First, we calculate the total possible selection (using combination)

$^nC_r = \frac{n!}{(n-r)!r!}$

So, we have:

$Total = ^{U + G}C_r$

$Total = ^{3 + 5}C_4$

$Total = ^8C_4$

$Total = \frac{8!}{(8-4)!4!}$

$Total = \frac{8!}{4!4!}$

Using a calculator, we have:

$Total = 70$

The number of ways of selecting 2 from 3 undergraduates is:

$U = ^3C_2$

$U = \frac{3!}{(3-2)!2!}$

$U = \frac{3!}{1!2!}$

$U = 3$

The number of ways of selecting 2 from 5 graduates is:

$G = ^5C_2$

$G = \frac{5!}{(5-2)!2!}$

$G = \frac{5!}{3!2!}$

$G =10$

So, the probability is:

$Pr = \frac{G * U}{Total}$

$Pr = \frac{10*3}{70}$

$Pr = \frac{30}{70}$

$Pr = 0.4286$

5 0

2 years ago