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slavikrds [6]
3 years ago
9

Pls help I’ve been getting bots all day! I really need help and I will give brainliest!

Mathematics
2 answers:
zaharov [31]3 years ago
6 0

Not a robot! I don't think.

Y in the beginning goes up to 3.

Y in the end goes down to -2 before shooting back up in an infinite sense.

Increasing: The beginning and the end the line on the graph. (Also the jump in the middle, the round part.)

Decreasing: The middle of the graph. (The jump, downward slope.)

Constant, Y at the near end going in a straight line from 9-12 at a -2.

End behavior: Decide for yourself. Is the line going up without fault at the end an appearing continuous or a discontinuous line?

Contact [7]3 years ago
6 0

Answer:

<u>End Behavior:</u>

x⇒-8,y⇒-∞

x⇒∞,y⇒∞

<h3>Increasing:</h3>

(-∞,1},{3,5},{12,∞)

<h3><u>Decreasing</u>:</h3>

{1,3},{5,9}

<h3><u>constant:</u></h3>

<u>(9,12)</u>

<u>hope it helps...</u>

<u>have a great day</u>

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Complete Question

The complete question is shown on the first uploaded image

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Step-by-step explanation:

From the question we are told that

        in every 1000 children a particular genetic defect occurs to 1

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The probability of not observing the defect is mathematically evaluated as

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The standard deviation of this probability is mathematically represented as

   \sigma = \sqrt{npq}

Substituting values

      = \sqrt{50000 * 0.001 * 0.999}

     = \sqrt{49.95}

     = 7.07

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       P(x \ge 60)

in standardizing the normal distribution the normal area used to approximate P(x \ge 60) is the right of 59.5 instead of 60 because  x= 60 is part of the observation

The z -score is obtained mathematically as

                z = \frac{x-\mu }{\sigma }

                   = \frac{59.5 - 50 }{7.07}

                  =1.34

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

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  The total area under the curve is 1

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    P(x \ge 60) \approx P(z > 1.34)

                     = 1-P(z \le 1.34)

                    =1-0.9099

                  =0.0901

             

   

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