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3 years ago

Which way do i turn it and wut are my points? will give brainliest

Mathematics

1 answer:

alexgriva [62]3 years ago

8 0

Answer:

Um...what is it that you want to create? What is the question? (please give me brainliest i need it so bad)

Step-by-step explanation:

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4(2x−3)=4(2x)−4(3) what is the proptery

Nikitich [7]

9514 1404 393

Answer:

distributive property

Step-by-step explanation:

The <em>distributive property</em> of multiplication over addition lets you expand the product in the manner shown.

4 0

3 years ago

I NEED HELP FAST!! PLZ.

adoni [48]

The answer is z = 4 because of you put 4 into the equation it equals to 100

3 0

3 years ago

A light bulb in Maya's house uses 9.4 watts of electric power each minute it is on. If the light bulb used a total of 6.58 watts

tamaranim1 [39]

Answer:

0.7 minute

Step-by-step explanation:

Given that each (1) minute a light use 9.4 watts.

So If the light bulb used a total of 6.58 watts, the minutes was on it is:

$\frac{The total watts used}{The watts used each minute}$

= $\frac{6.58}{9.4}$

= 0.7 minute

So the the minutes was on it is 0.7

Hope it will find you well!

4 0

3 years ago

What is the slope of a line perpendicular to the line passing through (1, -3) and (-4, 7)?

andrezito [222]

Answer:

-2

Step-by-step explanation:

m= $\frac{y2-y1}{x2-x1}$

7 0

4 years ago

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago