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Vlada [557]
3 years ago
7

Write the same ratio using another form A:B vs A to B

Mathematics
2 answers:
meriva3 years ago
7 0
A/b over another one
Firdavs [7]3 years ago
5 0
A over B like a.fraction
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Although the actual amount varies by season and time of​ day, the average volume of water that flows over the falls each second
lutik1710 [3]
Given that <span>the average volume of water that flows over the falls each second is 4.8 \times 10^5 gallons.

There are 3,600 seconds in one hour.

Thus, in one hour, 4.8 \times 10^5\times3600=17280\times10^5=1.728\times10^9 gallons of water </span><span>flows over the falls.

</span>Therefore, the amount of water that flows over the falls is <span>1.728\times10^9.</span>
3 0
2 years ago
Assume the population has a distribution with a mean of 110 and a standard deviation of 8. For a random sample of size 40, find
VARVARA [1.3K]

Answer:

109.33

Step-by-step explanation:

given that the population has a distribution with a mean of 110 and a standard deviation of 8

Sample size n = 40

Std error of sample mean = std dev/square root of sample size

= \frac{8}{\sqrt{40} } \\=1.265

From std normal distribution table we find that 30th percentile for Z is

-0.5244

Corresponding x score =110-0.5244*1.265=109.33663

30th percentile = 109.33663

=109.33

8 0
3 years ago
For the following pair of lines, identify the system by type.
Alexus [3.1K]

Equivalent lines for sure

7 0
2 years ago
The area of a playground is 266 yd. The width of the playground is 5 yd longer than its length. Find th
Mademuasel [1]

Answer:

C

Step-by-step explanation:

The width is 5 yds longer so we can mark out b and d if you multiply 19 and 24 is 456 so you are left with C

5 0
2 years ago
A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.
Crank

Answer: 1.25

Step-by-step explanation:

Given: A college-entrance exam is designed so that scores are normally distributed with a mean(\mu) = 500 and a standard deviation(\sigma) =  100.

A z-score measures how many standard deviations a given measurement deviates from the mean.

Let Y be a random variable that denotes the scores in the exam.

Formula for z-score = \dfrac{Y-\mu}{\sigma}

Z-score = \dfrac{625-500}{100}

⇒ Z-score = \dfrac{125}{100}

⇒Z-score =1.25

Therefore , the required z-score = 1.25

6 0
3 years ago
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