Please answer and explain how you received that answer, these are the three problems I had trouble with out of 18

Mathematics

1 answer:

Varvara68 [4.7K]3 years ago

5 0

9) x.14 = 6.26 ==> 14x=156 ==> x=11.1

12) OAB = Right Triangle : (27+24)² = 24² + AB² (Pythagoras)
==> 51² =24² + AB² ==> 2,601 = 576 + AB² ==> AB² = 2,601 - 576 = 2,025
==> AB² = 2015 AND AB =√2025 = 45
Sorry I can't read the last page

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Help a brother out!!! Math prom worth 20!! And explain please

Reil [10]

A.

ratio 1 to 1

alright
find the distance between the x values and the y values and seperate each into that ratio
1:1
A to B is (6,12) to (15,-4)
disatnce from 6 to 15 is 9, ratio would be 4.5:4.5=1:1
distance from 12 to -4 is 16, ratio would be 8:8=1:1
so the point would be (4.5,8)

b.
5:2
5+2=7
alright
A to C
(6,12) to (20,12)
distance from 6 to 20 is 14, 14/7=2, 2 times 5=10
distance from 12 to 12=0, so same coordinate
the point is (10,12)

c.
2+3=5

C to B
C is (20,12) and B is (15,-4)
distance from 20 to 15 is 5, so 2 is the x value
distance from 12 to -4 is 16, 16/5 times 2=32/5
the point is (2,32/5)

5 0

3 years ago

Let A be the area of a circle with radius r. If dr/dt=3, find dA/dt when r=2.

astraxan [27]

$\bf \textit{area of a circle}=A=\pi r^2
\\\\\\
\cfrac{dA}{dt}=\pi \cdot 2r^1\cdot \cfrac{dr}{dt}\implies \cfrac{dA}{dt}=\pi \cdot 2r\cdot \cfrac{dr}{dt}\quad 
\begin{cases}
r=2\\
\frac{dr}{dt}=3
\end{cases}
\\\\\\
\cfrac{dA}{dt}=\pi \cdot 2(2)(3)$