Question

To find the solutions to an equation of the form ax2+bx+c , use the quadratic equation: x=−b±b2−4ac√2a . What are the two solutions to 2x2−x−4=0 ? Use the quadratic equation. (Report the greater of the two solutions first, using 3 significant digits for both solutions)

Answer 1

Answer:

1.686

Step-by-step explanation:

Given is an quadratic equation as

$2x^2-x-4=0$

Also we are given the formula for general equation

$ax^2+bx+c$ as

$\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

Here in our equation we have

$a=2\\b=-1\\c=-4$

Hence solution would be

$\frac{1+\sqrt{1+32} }{4} ,\frac{1-\sqrt{1+32} }{4} \\\frac{1+\sqrt{33} }{4} ,\frac{1-\sqrt{33} }{4}$

Greater would be the one with positive square root

$\frac{1+\sqrt{33} }{4} \\=1.6861\\=1.686$

Answer 2

Answer:

Brahmagupta’s solution to a quadratic equation of the form ax2 + bx = c involved only one solution. Which solution would he have found for the equation 3x2 + 4x = 6?

first option.

To find the solutions to an equation of the form ax2+bx+c , use the quadratic equation: x=−b±b2−4ac√2a . What are the two solutions to 2x2−x−4=0 ? Use the quadratic equation. (Report the greater of the two solutions first, using 3 significant digits for both solutions)

third option.