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Tresset [83]
3 years ago
13

Drag the amounts to order them from greatest to least. 1 lb = 16 oz 1 oz ≈ 28.3 g 800 g1.6 lb30 oz

Mathematics
2 answers:
VladimirAG [237]3 years ago
8 0
So, problem statement tells you that 1lb = 16oz and that 1oz = 28.3g. That means that 1lb = 16 * 28.3g = 452.8g
You have three items, convert their weights to grams:1) 800g2) 1.6lb = 1.6 * 452.8g = 724.48g3) 30oz = 30 * 28.3g = 849g
So, sorting from greatest:3, 2, 1, or: 30oz, 1.6lb, 800g.
 
Tpy6a [65]3 years ago
6 0
The Answer is : 30 oz  -  800g    -    16lb

How I know is that I finished the test.
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djyliett [7]

Answer:

they got -21 when they were supposted to get +21

and they also got +6x when they were supposted to get -6x

Step-by-step explanation:

that's because -3 and 2x are multiplied together and when you are multiplying negative and positive number you need to get negative result.

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8 0
3 years ago
If AB is parallel to CD, and CD = 20, BD = 6, DE = 8, what is the length of AB?
castortr0y [4]

Answer:

Option b. 35 units

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

in this problem triangle ABE and triangle CDE are similar by AA Similarity Theorem

so

\frac{AB}{DC}=\frac{BE}{DE}

substitute the given values

\frac{AB}{20}=\frac{14}{8}

Solve for AB

AB=\frac{14}{8}(20)

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5 0
3 years ago
The given line passes through the points (-2,-4) and (2,2) What is the equation, in point-slope form, of the line that is parall
Morgarella [4.7K]

Answer:

(y-1)=\frac{3}{2}(x+3)


Step-by-step explanation:

The point slope form of a line is (y-y_1)=m(x-x_1) where x_1=-3\\y_1=1. We write  

(y-1)=m(x--3)\\(y-1)=m(x+3)


Since the line is parallel to the line shown it will have the same slope. To find m, count the slope from each marked point on the graph. Count the rise then the run and create a fraction rise/run. The slope is 6/4 which simplifies to 3/2. Now substitute it for m.

(y-1)=\frac{3}{2}(x+3)




3 0
3 years ago
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