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Tresset [83]
3 years ago
13

Drag the amounts to order them from greatest to least. 1 lb = 16 oz 1 oz ≈ 28.3 g 800 g1.6 lb30 oz

Mathematics
2 answers:
VladimirAG [237]3 years ago
8 0
So, problem statement tells you that 1lb = 16oz and that 1oz = 28.3g. That means that 1lb = 16 * 28.3g = 452.8g
You have three items, convert their weights to grams:1) 800g2) 1.6lb = 1.6 * 452.8g = 724.48g3) 30oz = 30 * 28.3g = 849g
So, sorting from greatest:3, 2, 1, or: 30oz, 1.6lb, 800g.
 
Tpy6a [65]3 years ago
6 0
The Answer is : 30 oz  -  800g    -    16lb

How I know is that I finished the test.
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Check the picture below.


based on the equation, if we set y = 0, we'd end up with 0 = 0.5(x-3)(x-k).

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since the triangle is made by the x-intercepts and y-intercepts, then the parabola most likely has another x-intercept on the negative side of the x-axis, as you see in the picture, so chances are "k" is a negative value.

now, notice the picture, those intercepts make a triangle with a base = 3 + k, and height = y, where "y" is on the negative side.

let's find the y-intercept by setting x = 0 now,


\bf y=0.5(x-3)(x+k)\implies y=\cfrac{1}{2}(x-3)(x+k)\implies \stackrel{\textit{setting x = 0}}{y=\cfrac{1}{2}(0-3)(0+k)} \\\\\\ y=\cfrac{1}{2}(-3)(k)\implies \boxed{y=-\cfrac{3k}{2}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of a triangle}}{A=\cfrac{1}{2}bh}~~ \begin{cases} b=3+k\\ h=y\\ \quad -\frac{3k}{2}\\ A=1.5\\ \qquad \frac{3}{2} \end{cases}\implies \cfrac{3}{2}=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)


\bf \cfrac{3}{2}=\cfrac{3+k}{2}\left( -\cfrac{3k}{2} \right)\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{2}}{3=\cfrac{(3+k)(-3k)}{2}}\implies 6=-9k-3k^2 \\\\\\ 6=-3(3k+k^2)\implies \cfrac{6}{-3}=3k+k^2\implies -2=3k+k^2 \\\\\\ 0=k^2+3k+2\implies 0=(k+2)(k+1)\implies k= \begin{cases} -2\\ -1 \end{cases}


now, we can plug those values on A = (1/2)bh,


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