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3 years ago

Drag the amounts to order them from greatest to least. 1 lb = 16 oz 1 oz ≈ 28.3 g 800 g1.6 lb30 oz

2 answers:

8 0

So, problem statement tells you that 1lb = 16oz and that 1oz = 28.3g. That means that 1lb = 16 * 28.3g = 452.8g
You have three items, convert their weights to grams:1) 800g2) 1.6lb = 1.6 * 452.8g = 724.48g3) 30oz = 30 * 28.3g = 849g
So, sorting from greatest:3, 2, 1, or: 30oz, 1.6lb, 800g.

Tpy6a [65]3 years ago

6 0

The Answer is : 30 oz - 800g - 16lb

How I know is that I finished the test.

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The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and

NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

$60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120$

Let's find h with the quadratic formula:

$\fbox {Quadratic formula:} \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}$

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation

$\fbox {Pythagorean equation:}$ <em>The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle). </em>

The base and the height are our legs. We will use "H" for the hypotenuse

$H^2 = b^2 + h^2 = 15^2 + 8^2 = 289\\ H = \sqrt {289} = 17$

H = 17

If we decrease the base and the height by 2 centimeters, we have

b' = 15 - 2 = 13 and h' = 8 - 2 = 6

With this, let's calculate the new hypotenuse:

$H'^2 = b'^2 + h'^2 = 13^2 + 6^2 = 205\\ H' = \sqrt {205} \approx 14.3$

$H' \approx 14.3$

So, the hypotenuse decreases $H - H' \approx 17 - 14.3 = 2.7$

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3 years ago

Someone please help me! ‘The value of X is...’

8_murik_8 [283]

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3 years ago

Alice and her friend Emma leave on different flights from the same airport. Alice's flight flies 100 miles due south, then turns

DaniilM [7]

9514 1404 393

Answer:

Emma's flight is farther from the airport

Step-by-step explanation:

Even without doing any detailed calculation, you can see on a graph that the larger turn Alice's flight makes keeps it closer to the airport.

Emma's flight is farther from the airport.

The distance can be calculated using the Law of Cosines. The angle of interest is the supplement of the turn angle. Since the leg distances are the same in each case, the only variable affecting the distance from the airport is the angle measure. Again, the larger the turn, the shorter the distance from the airport. If T is the turn angle, the distance is ...

d² = 100² +50² -2·100·50·cos(180° -T)

d² = 12500 +10000·cos(T) . . . . . . . using cos(180°-T) = -cos(T)

d = 100√(1.25+cos(T))

For Alice's 70° turn, the distance is ...

d = 100√(1.25+0.342) ≈ 126.18 mi

For Emma's 50° turn, the distance is ...

d = 100√(1.25 +0.643) ≈ 137.58 mi

Emma's flight is farther from the airport.

_____

The law of cosines formula is ...

c² = a² +b² -2ab·cos(C)

where triangle sides are lengths a, b, c and angle C is opposite side c.

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3 years ago