Question

The average test scores for a particular test in algebra was 84 with a standard deviation of 5. What percentage of the students scored higher than 89%? Please explain your answer.

Answer 1

Answer:

The percentage of the students scored higher than 89% is 15.87%

Step-by-step explanation:

we are given

The average test scores for a particular test in algebra was 84

so, mean is 84

$\mu=84$

a standard deviation of 5

so,

$\sigma=5$

we have

x=89

now, we can use z-score formula

$z=\frac{x-\mu}{\sigma}$

now, we can plug values

$z=\frac{89-84}{5}$

$z=1$

now, we can use calculator

and we get

$p(z>1)=0.1587$

So,

The percentage of the students scored higher than 89% is 15.87%