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1 year ago

Simplify 2x^2-7x-4/x^2

Mathematics

1 answer:

kvv77 [185]1 year ago

4 0

Answer:

Option 1

Step-by-step explanation:

$\frac{2x^2 - 7x-4}{x^2 - 5x+4}=\frac{(x-4)(2x+1)}{(x-4)(x-1)}=\frac{2x+1}{x-1}$

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Work out angle bxc. give a reason for each angle you work out

Rus_ich [418]

Answer:

∠ BXC = 70°

Step-by-step explanation:

∠ XBC and ∠ AXY are corresponding angles and are congruent, then

∠ XBC = 55°

Since XB = XC , then Δ XBC is isosceles and the 2 base angles are congruent.

∠ BXC = 180° - (55 + 55)° ← angle sum of triangle

∠ BXC = 180° - 110° = 70°

7 0

2 years ago

What is the value of this expression?

saw5 [17]

Answer:

Hey

Step-by-step explanation:

Answer is b. 42

2(17+6)−4

8 0

2 years ago

Read 2 more answers

I don’t understand how to identify quadratic transformations. Can I have so help please?

Levart [38]

Answer:

The parent function for a quadratic is f(x) = x^2. If there is something other than this, that is how you know it is a quadratic transformation.

8 0

2 years ago

‼️10 points‼️

Tamiku [17]

Answer:

<h3>The answer is option D.</h3>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

Slope of the line using points ( 5 , - 1) and

( - 5 , 2) is

m = 2+1/ -5-5 = - 3 / 10

Equation of the line using point ( 5 , - 1) is

y + 1 = -3/10(x - 5)

y = -3/10x + 3/2 - 1

The final answer is

Hope this helps you.

4 0

3 years ago

There are premium tickets costing $99 each and rest are regualr tickets costing $25 each. A pile of 120 tickets have a total val

polet [3.4K]

Answer:

There are 38 premium tickets and 82 regular tickets in a pile.

Step-by-step explanation:

Given,

Total number of tickets = 120

Total amount = $5812

Solution,

Let the number of premium tickets be x.

And the number of regular tickets be y.

Total number of tickets is the sum of total number of premium tickets and total number of regular tickets.

So the equation can be written as;

$x+y=120\ \ \ \ \ equation\ 1$

Again,total amount is the sum of total number of premium tickets multiplied by cost of each premium ticket and total number of regular tickets multiplied by cost of each regular ticket.

So the equation can be written as;

$99x+25y=5812\ \ \ \ equation\ 2$

Now We will multiply equation 1 by 25 we get;

$x+y=120\\25(x+y)=120\times25\\25x+25y= 3000 \ \ \ \ equation\ 3$

Now Subtracting equation 3 from equation 2 we get;

$(99x+25y)-(25x+25y)=5812-3000\\\\99x+25y-25x-25y=2812\\\\74x=2812\\\\x=\frac{2812}{74}=38$

We will now substitute the value of x in equation 1 we get;

$x+y=120\\38+y=120\\y=120-38\\y=82$

Hence There are 38 premium tickets and 82 regular tickets in a pile.

3 0

3 years ago