Question

Translate into an algebraic expression: n−1 increased by 110%

Answer 1

Answer:

Part 1) The algebraic expression is equal to $1.10(n-1)$  or $1.10n-1.10$

Part 2) The algebraic expression is equal to $\frac{1.10}{n}$

Step-by-step explanation:

Part 1) we have (n-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

$1.10(n-1)$

Distributed

$1.10n-1.10$

Part 2) we have n^(-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)

Remember that

$n^{-1}=\frac{1}{n}$

so

$1.10(n^{-1})=1.10\frac{1}{n}=\frac{1.10}{n}$