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Hunter-Best [27]
3 years ago
8

Translate into an algebraic expression: n−1 increased by 110%

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
4 0

Answer:

Part 1) The algebraic expression is equal to 1.10(n-1)  or 1.10n-1.10

Part 2) The algebraic expression is equal to \frac{1.10}{n}

Step-by-step explanation:

Part 1) we have (n-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

1.10(n-1)

Distributed

1.10n-1.10

Part 2) we have n^(-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)

Remember that

n^{-1}=\frac{1}{n}

so

1.10(n^{-1})=1.10\frac{1}{n}=\frac{1.10}{n}

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Answer:

b) 0.0007

c) 0.4163

d) 0.2375

Step-by-step explanation:

We are given the following:

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Then the securities lose value follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

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We have to evaluate:

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0.0007 is the probability that all 20 securities lose value.

c) P(at least 15 of them lose value.)

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Answer:

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