The domain is x and the range is f(x)
Answer:
A. Function 1
Step-by-step explanation:
The slope of Function 2 can be found using the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (-8 -(-2))/(3 -0) = -6/3
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The slope of function 1 can be found by comparing the equation to the slope-intercept equation for a line:
y = mx + b . . . . . . equation with slope m and y-intercept b
The slope of Function 1 is -7/3.
-7/3 is more negative than -6/3, so Function 1 has the more negative slope.
X^2+y^2 = 16
can be written as
(x-0)^2+(y-0)^2 = 4^2
We see that the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2
where
(h,k) = (0,0) is the center
r = 4 is the radius
The polar form of the equation is simply r = 4. Why is this? Because the radius is fixed to be 4 no matter what happens with theta. As theta goes from 0 to 360, the points generated all form a circle centered at (0,0) with radius 4.
Answer: r = 4
Answer:
1. -6y^4 +4y^2 -12
2. x - 19
Step-by-step explanation:
1.
(6y^4+3y^2-7) - (12y^4-y^2+5)
= -6y^4+ 4y^2- 12
2. 3(x-5) - (3x+4)
= (3x-15) - (3x+4)
= x-19
