What is the Distribution property of multiply addends of number,the add the products

1. 112 2. 136 3. 68 4. 158 5. 129

RideAnS [48]

Answer:

4. 158

Step-by-step explanation:

First let's make things a little simpler and put these arcs in terms of x. We know that the degree measure around the outside of a circle, regardless of its size, is 360. So let's say that arc BC is x. That means that arc BDC is 360 - x. This is because arc BC + arc BDC = 360. Substituting in our x's we have:

x + 360 - x = 360 and

360 = 360. (That's just the proof that putting in our x's as we did does in fact work!)

Following the formula then, we have

$22=\frac{1}{2}(360-x-x)$ and

$22=\frac{1}{2}(360-2x)$

Multiply both sides by 2 to get rid of the fraction and get

44 = 360 - 2x

Subtract 360 rom both sides to get

-316 = -2x

Divide both sides by -2 to get that x = 158

Since we are looking for arc BC and we designated arc BC as our x, that means that arc BC = 158.

3 0

4 years ago

Finish solving the system of equations -9.5x -2.5y = -4.3 and 7x + 2.5y = 0.8 using the linear combination method.

muminat

Answer:

y= -3.6

Step-by-step explanation:

-9.5(1.4)-2.5y=-4.3

-13.3-2.5y=-4.3

-9=2.5y

y=-3.6

4 0

3 years ago

Please explain how you got the answer also, thank you

harina [27]

Answer:

See Explanation

Step-by-step explanation:

You are doing simple math within the square root. For instance where x=-2 you substitute -2 for x then add 2 which gives you 0 leaving you with -6.

for x=2 you end up with "square root 2+2" which gives you 4 and the square root of 4 is 2 so you add -6 to 2 giving you the answer of -4.

7 0

3 years ago

How to calculate 146 divided by 397 step by step to get the result 0,3377

topjm [15]

it just keeps going . You keep adding the zero and subtracting.

5 0

3 years ago

Point A is at (2,-8) and the point C is at (-4,7). Find the coordinates of point B on AC such that the ratio of AB to BC is 2:1.

pentagon [3]

Answer:

The coordinates of point B are (-2, 2)

Step-by-step explanation:

We have two points: A and C.

The coordinates for A are (2, -8) and the coordinates for C are (-4, 7).

We have to find the coordinates of the point B, that satisfies the condition that the distance AB is 2 times the distance BC.

We also know that B is a point of the line AC.

We can calculate the line AC as a linear function y=mx+b.

The slope m is:

$m=\dfrac{y_c-y_a}{x_c-x_a}=\dfrac{7-(-8)}{-4-2}=\dfrac{15}{-6}=-2.5$

Then, the y-intercept b can be calculated using the coordinates of one of the points, in this case point A:

$y=-2.5x+b\\\\b=y_a+2.5x_a=-8+2.5*2=-8+5=-3$

Then, we know that B is a point of the linear function y=-2.5x-3, within the range x ∈ (-4; 2).

To have a ratio AB to BC of 2 to 1, we can divide the length of the line AC in 3 parts, and the point B will be located in the end of the segment nearer to point C.

In the picture attached, you can see the division of the segment AC in three parts and the location of point B=(x, y).

Applying the Thales theorem, we can divide the segment in the y-axis in three and calculate y, and the same for the x-axis.

Then, the coordinate y for the point B is:

$y=y_c-(y_c-y_a)/3\\\\y=7-[7-(-8)]/3=7-15/3=7-5=2\\\\\\x=x_c-(x_c-x_a)/3\\\\x=-4-(-4-2)/3=-4-(-6)/3=-4+2=-2$

Then, the point B has coordinates (-2, 2).

We can verify the distances as:

$AB=\sqrt{(2-(-2))^2+((-8)-2)^2}=\sqrt{16+100}=\sqrt{116}\\\\\\BC=\sqrt{((-2)-(-4))^2+(2-7)^2}=\sqrt{4+25}=\sqrt{29}\\\\\\\dfrac{AB}{BC}=\dfrac{\sqrt{116}}{\sqrt{29}}=\sqrt{\dfrac{116}{29}}=\sqrt{4}=2$

4 0

3 years ago