All categories

3 years ago

If a small boy, in 30 days, saved $1.00 to spend in your store, how much did he save each day?

Mathematics

2 answers:

kirza4 [7]3 years ago

8 0

Answer:

He saved 3.3 cents for 29 days and 4.3 cents for one day.

(This means a minimum of 3.3 cents each day)

Step-by-step explanation:

We divide the total amount saved by the number of days it took to save the money.

i.e $1.00 divided by 30 days

$\frac{1}{30} = 0.033$

He saves a minimum of $0.033 each day for 30 days

However, if he only saves $0.033 cents, he would have saved $0.99 on the thirtieth day.

0.033 x 30 = $0.99

This means he would be $0.01 short

Therefore, in order to have $1.00, he must save an extra $0.01 on one of the 30 days

This means he would save 0.033 + 0.01 = $0.043 for one day.

Where $1.00 = 100 cents

$0.033 = 3.3 cents

$0.01 = 1 cent

$0.043 = 4.3 cents

He saved 3.3 cents for 29 days and 4.3 cents for one day

3.3 x 29 = 95.7 cents

4.3 x 1 = 4.3 cents

95.7 + 4.3 = 100 cents

100 cents = $1.00

ivolga24 [154]3 years ago

6 0

Answer:

3 cents for 29 days and 4 cents for 1 day

Step-by-step explanation:

1.00 dollar / 30 days = .03 cents

3 cents x 30 = .99 cents

3 cents for 29 days and 4 cents for 1 day

You might be interested in

I NEED HELP!!! PLEASE HELP!!! FIRST TO ANSWER GETS 50 POINTS AND BRAINLIEST ANSWER!!! HEEELLPPPP!!!! Find the distance between p

daser333 [38]

Answer:

8.6 to the nearest tenth.

Step-by-step explanation:

Using the distance formula d = √ [(y2 - y1)^2 + (x2 - x1)^2] where (x1, y1) and (x2, y2) are the two endpoints.

= √ (4 - -3)^2 + (-3-2)^2

= √(49 + 25)

= 8.60

6 0

3 years ago

55 POINTS ASAP

QveST [7]

Step-by-step explanation:

Option B. Here Adam Ct. is perpendicular to Betha Dr. and Charles. So, St. Bertha Dr. || Charles St. Since they are parallel to each other

8 0

3 years ago

Read 2 more answers

A number plus 1/3 of the number can be expressed as:

nirvana33 [79]

Answer:

n+n/3

Step-by-step explanation:

n+1/3 n=n+n/3=4n/3

Please mark as Brainliest! :)

Have a nice day.

6 0

3 years ago

8) Monica spent $34 on brownies and cookies. We know brownies cost $2

Anna [14]

The answer is

2b + .75c = 34

3 0

3 years ago

Read 2 more answers

The curve

kherson [118]

Answer:

Point N(4, 1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Anything to the 0th power is 1
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \sqrt{x - 3}$

$\displaystyle y' = \frac{1}{2}$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y = (x - 3)^{\frac{1}{2}}$
Chain Rule: $\displaystyle y' = \frac{d}{dx}[(x - 3)^{\frac{1}{2}}] \cdot \frac{d}{dx}[x - 3]$
Basic Power Rule: $\displaystyle y' = \frac{1}{2}(x - 3)^{\frac{1}{2} - 1} \cdot (1 \cdot x^{1 - 1} - 0)$
Simplify: $\displaystyle y' = \frac{1}{2}(x - 3)^{-\frac{1}{2}} \cdot 1$
Multiply: $\displaystyle y' = \frac{1}{2}(x - 3)^{-\frac{1}{2}}$
[Derivative] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{1}{2(x - 3)^{\frac{1}{2}}}$
[Derivative] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y' = \frac{1}{2\sqrt{x - 3}}$

Step 3: Solve

Find coordinates

x-coordinate

Substitute in y' [Derivative]: $\displaystyle \frac{1}{2} = \frac{1}{2\sqrt{x - 3}}$
[Multiplication Property of Equality] Multiply 2 on both sides: $\displaystyle 1 = \frac{1}{\sqrt{x - 3}}$
[Multiplication Property of Equality] Multiply √(x - 3) on both sides: $\displaystyle \sqrt{x - 3} = 1$
[Equality Property] Square both sides: $\displaystyle x - 3 = 1$
[Addition Property of Equality] Add 3 on both sides: $\displaystyle x = 4$