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Ket [755]
3 years ago
8

Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans

wer a list of questions. Part A: For what one value of x are the perimeters of the quadrilaterals the same? (Hint: The perimeter of a quadrilateral is the sum of its sides.) Part B: For what one value of x are the areas of the quadrilaterals the same? (Hint: The area of a quadrilateral is the product of its base and height.)

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0

A) 6+x+4 = 2+3x+4

10+x = 3x+6

10 = 2x+6

4 = 2x

x = 4/2

x = 2


B)

6 * (x+4) = 2 *(3x+4) =

6x+24 = 6x+8

 there is no solution for part B


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Find equations of both the tangent lines to the ellipse x^2 + 4y^2 = 36 that pass through the point (12, 3).y = (smaller slope)y
Bingel [31]

Answer:

x+y=15

Step-by-step explanation:

Given equation of x^2+4y^2=36

Differentiating both side 2x+8y\frac{dy}{dx}=0

\frac{dy}{dx}=\frac{-x}{4y}

It passes through the point (12,3) so

\frac{dy}{dx}=\frac{-12}{4\times 3}=1

So equation of tangent passing through (12,3) is

y-12=-1(x-3) as y-y_1=-m(x-x_1)

So x+y =15 will be the equation of tangent which passes though the point (12,3)

5 0
3 years ago
What sum of money amounts to rupees 8700 in 3 years at the rate of 24 % per annum​
Zina [86]

Given:

Amount = 8700

Time = 3 years

Rate of interest = 24% per annum

To find:

The principal values.

Solution:

Formula for amount:

A=P\left(1+\dfrac{r}{100}\right)^t

Where, A is amount, P is principal, r is the rate of interest and t is the number of years.

Putting A=8700,r=24,t=3, we get

8700=P\left(1+\dfrac{24}{100}\right)^{3}

8700=P\left(1+0.24\right)^{3}

8700=P\left(1.24\right)^{3}

8700=1.906624P

Divide both sides by 1.906624.

\dfrac{8700}{1.906624}=P

4563.0391729=P

P\approx 4563.04

Therefore, the principal value is about 4563.04.

8 0
3 years ago
A restaurant manager has the option of a 30-year loan of $417,000 at an annual interest rate of 3.85% or the same interest rate
victus00 [196]

a) The monthly payment for each loan is as follows:

30-year $1,954.93

15-year $3,053.25

b) The savings in interest by using the 15-year loan is <u>$154,189,20</u> ($286,774.20 - $132,585).

c) No. the monthly payment for the 15-year loan is <u>not twice</u> that of the 30-year loan as the loan term.

d) The interest savings for the 15-year loan are <u>more</u> than one-half of the interest paid on the 30-year loan.

<h3>How are the calculations for periodic payments done?</h3>

The calculations for the monthly payments, including interests can be carried out using an online finance calculator, as follows:

<h3>30-year Loan:</h3>

N (# of periods) = 360 months (12 x 30 years)

I/Y (Interest per year) = 3.85%

PV (Present Value) = $417000

FV (Future Value) = $0

<u>Results</u>:

PMT = $1,954.93

Sum of all periodic payments = $703,774.80 ($1,954.93 x 360)

Total Interest = $286,774.20 ($703,774.80 - $417,000)

<h3>15-year Loan:</h3>

N (# of periods) = 180 months (12 x 15 years)

I/Y (Interest per year) = 3.85%

PV (Present Value) = $417000

FV (Future Value) = $0

<u>Results</u>:

PMT = $3,053.25

Sum of all periodic payments = $549,585 ($3,053.25 x 180)

Total Interest = $132,585 ($549,585 - $417,000)

Learn more about periodic payments at brainly.com/question/13098072

#SPJ1

7 0
1 year ago
Help plz?????????????????
SCORPION-xisa [38]

Answer:

$11.40

Step-by-step explanation:

40%=.40

11.00+0.40

=$11.40

6 0
3 years ago
Read 2 more answers
If cos θ = .62 and if 0&lt;θ&lt;90 what is the approximate value of sin θ to the nearest hundredth
Deffense [45]
\cos\Theta=0.62\\\\\text{Use:}\ \sin^2\alpha+\cos^2\alpha=1\\\\\sin^2\Theta+(0.62)^2=1\\\\\sin^2\Theta+0.3844=1\ \ \ |-0.3844\\\\\sin^2\Theta=0.6156\to\sin\Theta=\pm\sqrt{0.6156}\\\\\sin\Theta_1\approx-0.78\ \vee\ \sin\Theta\approx0.78\\\\\Theta\in(0^o;\ 90^o),\ therefore\ \sin\Theta \ \textgreater \  0\to\boxed{\sin\Theta\approx0.78}
5 0
3 years ago
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