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MariettaO [177]
3 years ago
5

What’s the answer???(SOMEONE PLEASE HELP ME)

Mathematics
1 answer:
kati45 [8]3 years ago
4 0
The answer is B. It does not represent a function because a vertical line will cross the graph at more than one point
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Find the distance between each pair of points. (6, -1), (6,-4)
Nady [450]

Answer:

The distance is 3.

Step-by-step explanation:

Since the x coordinates are the same, we take (-1)-(-4) = 3.

7 0
2 years ago
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Which polynomial function has a leading coefficient of 1 and roots (7 i) and (5 – i) with multiplicity 1? f(x) = (x 7)(x – i)(x
Nuetrik [128]

It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.

The simplest polynomial with these characteristics would be

f(x) = (x - (7 + i)) (x - (5 - i))

but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with

f(x) = (x - (7 + i)) (x - (7 - i)) (x - (5 - i)) (x - (5 + i))

which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients:

f(x) = (x^2 - (7^2 - i^2)) (x^2 - (5^2 - i^2)) = (x^2 - 8) (x^2 - 6) = x^4 - 14x^2 + 48

5 0
2 years ago
Define perpendicular bisector​
tresset_1 [31]

Answer:

Step-by-step explanation:

A perpendicular bisector is a special kind of segment, ray, or line that. (1) intersects a given segment at a 90° angle, and. (2) passes through the given segment's midpoint. Segment CD is the perpendicular bisector to segment AB. We derive two important theorems from the characteristics of perpendicular bisectors.

7 0
3 years ago
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What's 60,488 rounded to the nearest ten thousand?
Lubov Fominskaja [6]
the answer is 60000 to the nearest 1000
4 0
3 years ago
Plzzz help the problem is <br> in the photo
Black_prince [1.1K]

Answer:

Step-by-step explanation:

A. 16.6%

B. 16.6%

1/3 x 1/2 = .166 = 16.6%

6 0
2 years ago
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