I need some help please.
1 answer:
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Answer:
See Explanation
Step-by-step explanation:
You are doing simple math within the square root. For instance where x=-2 you substitute -2 for x then add 2 which gives you 0 leaving you with -6.
for x=2 you end up with "square root 2+2" which gives you 4 and the square root of 4 is 2 so you add -6 to 2 giving you the answer of -4.
Answer:
The image in the attached figure
Step-by-step explanation:
we know that
The dimensions of the image of the given triangle are equal to the original dimensions of the pre-image multiplied by the scale factor
In this problem the scale factor is 1/4
The height of the pre-image is 4 units
The base of the pre-image is 8 units
Find out the dimensions of the image
The height of the image is
The base of the image is
The image in the attached figure
Answer:
3
Step-by-step explanation:
And,
$ \sum (2i+1)= \sum (2i)+ \sum_{i=1} ^{4} (1) $
$=\sum_{i=1} ^{4}(2i) + 1+1+1+1 $
$=\boxed{\Big(\sum_{n=1} ^{4}(2n)\Big) +4}.... \text{Variable in Summation doesn't matter}$
Hence the difference is 3.
