Given:
The statement is "two sevenths times four sixths".
To find:
The value of the product.
Solution:
Two sevenths times four sixths can be written as:
It can be rewritten as:
The answer of given expression is eight forty seconds.
Therefore, the correct option is B.
Answer:
A)
Step-by-step explanation:
the solution of a squared equation is
x = (-b ± sqrt(b² - 4ac)) / (2a)
in our case
a = 1
b = 8
c = 22
x = (-8 ± sqrt(64 - 88))/2 = (-8 ± sqrt(-24))/2 =
= (-8 ± sqrt(4×-6))/2 = (-8 ± 2×sqrt(-6))/2 =
= -4 ± sqrt(-6) = -4 ± i×sqrt(6)
Answer:
t = 1.107
Step-by-step explanation:
Finding the solution using derivatives involves finding the lower zero of the quadratic that is the second derivative of the given function. That second derivative will be ...
f''(t) = 12(1.6714)t^2 -6(22.45)t +2(62.27)
= 20.0568t^2 -134.7t +124.54
= 20.0568(t -3.35796)² -101.619 . . . . rewrite to vertex form
Then f''(t) = 0 when ...
t ≈ 3.35796 -√(101.619/20.0568) ≈ 1.10706
__
The solution is perhaps more easily found using a graphing calculator to find the peak of the first derivative. (See attached.) It tells us ...
t ≈ 1.107
1.1 years after the beginning of 1998 is about 1.2 months into 1999.
Rents were increasing most rapidly in early February of 1999.
3.14 by 3.57 just divide those numbers by 14 and round to the hundredths place
Answer:
2 m
Step-by-step explanation:
Here the area and the lengths of the two parallel sides of this trapezoid are given:
A = 7m^2, b1 = 3 m and b2 = 4 m. What's missing is the width of the trapezoid.
First we write out the formula for the area of a trapezoid:
b1 + b2
A = --------------- * w, where w represents the width of the figure.
2
We need to solve this for the width, w. Multiplying both sides of the above equation by
2
------------
b1 + b2
results in
2A
------------ = w
b1 + b2
Substituting 7 m^2 for A, 3 m for b1 and 4 m for b2 results in
2(7 m^2) 14 m^2
w = ------------------ = ---------------- = 2 m
(3 + 4) m 7 m
The missing dimension is the width of the figure. This width is 2 m.
