y = |x - 3|
3x + 3y = 27
3x + 3|x - 3| = 27
3x + 3|x - 3| = ±27
3x + 3|x - 3| = 27 or 3x + 3|x - 3| = -27
3x + 3(x - 3) = 27 or 3x + 3(x - 3) = -27
3x + 3(x) - 3(3) = 27 or 3x + 3(x) - 3(3) = -27
3x + 3x - 9 = 27 or 3x + 3x - 9 = -27
6x - 9 = 27 or 6x - 9 = -27
+ 9 + 9 + 9 + 9
6x = 36 or 6x = -18
6 6 6 6
x = 6 or x = -3
y = |x - 3| or y = |x - 3|
y = |6 - 3| or y = |-3 - 3|
y = |3| or y = |-6|
y = 3 or y = 6
(x, y) = (6, 3) or (x, y) = (-3, 6)
The two systems of equations of the graph is only equal to (6, 3). It is not equal to (-3, 6) because one of the systems of equations - y = |x - 3| - only has one solution to the function. So the answer to the problem is 3 - (6, 3) is the solution to the system because it satisfies both equations.
Answer by JKismyhusbandbae: (I don't know if you wanted me to factor because you weren't specific but you can't simplify this.)
All the angles added up = 360°
46 + 4x - 2 + 9x + 6 + 8x - 5 = 360
21x + 45 = 360
21x = 315
x = 15
Let me know if you have questions.
Answer: see table
<u>Step-by-step explanation:</u>
The number of weeks are multiples of 2 (every 2 weeks) and the number of paintings are multiples of 7 (7 paintings every 2 weeks).
Answer:
50,000
Step-by-step explanation:
1st car had $1,750 tax
2nd car has $3,500 tax
1750(2) = 3500
so your tax doubled so the price must be doubled.
The car is $50,000
Algebraically using direct variation:
t = kp where t=tax, p = purchase price,
and k is constant of variation
1750 = 25000k
k = 1750/25000
k = 0.07
Your equation is: t = 0.07p
3500 = 0.07p
p = 3500/0.07
p = $50,000