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Blizzard [7]
3 years ago
11

DO MOBILE DEVICES HAVE TO WORK IN LIMITED SCREEN SPACE

Computers and Technology
2 answers:
Taya2010 [7]3 years ago
8 0
Yes, mobile devices have to work in limited screen space.
Alexxx [7]3 years ago
3 0
Yes, Mobile devices have to work on limited screen space because the screen of the device couldn't overcome the devices inside functions such as the speakers causing malfunctions
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List pros and cons of HCI technology​
Verdich [7]
A pro of HCI technology is that its user friendly and a con about it is that you have to teach the user what to do or guide them!
8 0
3 years ago
Read 2 more answers
Create a program in Matlab that prints the numbers from 1-100.
Burka [1]

Answer:

numbers = 1:1:100;

for num=numbers

remainder3 = rem(num,3);

remainder5 = rem(num,5);

 

if remainder3==0

disp("Yee")

else

if remainder3 == 0 && remainder5 == 0

disp ("Yee-Haw")

else

if remainder5==0

disp("Haw")

else

disp("Not a multiple of 5 or 4")

end

end

end  

end

Explanation:

  • Initialize the numbers variable from 1 to 100.
  • Loop through the all the numbers and find their remainders.
  • Check if a number is multiple of 5, 3 or both and display the message accordingly.
4 0
3 years ago
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For f
julia-pushkina [17]

Complete Question:

Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?

Answer:

a) 51.2 msec.  b) 5.12 msec

Explanation:

If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:

  • Tw = K*512* bit time

The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:

a) BW  = 1 Mbps = 10⁶ bps

⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec

b) BW = 10 Mbps = 10⁷ bps

⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec

5 0
3 years ago
- Create a Java program in both Windows and Ubuntu using any of their Editors *** DO NOT USE IDE'S SUCH AS ECLIPSE, NETBEANS, ET
Marat540 [252]

Answer:

Following are the code to this question:

public class ArrayMath//defining a class ArrayMath

{

public static void main(String[] args) //defining main method

{

int x[][]=new int[10][10]; //defining a 2D array  

arrays(x);//calling a method arrays by passing an array

}

private static void arrays(int[][] x)//defining a method arrays

{

int odd_column_sum=0,sum_of_Elements=0,i,j,even=1;//defining integer variable  

for(i=0;i<x.length;i++)//defining loop for columns  

{

for(j=0;j<x[0].length;j++)//defining loop for rows

{

x[i][j]=i*j;//multiply the i and j value atore in array

}

}

System.out.println("::The 2D array :: ");//print message

for(i=0;i<x.length;i++)//defining loop for columns

{

System.out.print("\t");//use print method for line space and line break  

for(j=0;j<x[0].length;j++)//defining loop for rows

{

System.out.printf("%d\t",x[i][j]); //print array values

}

System.out.println( );//print for line break

}

for(i=0;i<x.length;i++) //defining loop for Columns

{

for(j=0;j<x[0].length;j++) //defining loop for rows

{

if(even%2!=0)//defining if block for check odd number condition

{

odd_column_sum+=x[j][i];//add odd number of array

}

sum_of_Elements+=x[i][j];//add even number of array

}

even++;//increment even variable value by 1

}

System.out.println("The sum of Odd Columns:"+odd_column_sum);//print odd_column_sum value

System.out.println("The array elements :"+sum_of_Elements);//print sum_of_Elements value

}

}

Output:

please find attached file.

Explanation:

In the above-given code, a class "ArrayMath" is defined, inside the class the main method is declared, which define a 2D array "x", this stores 10 columns and 10 rows and at the last, we call the arrays method by passing an array as a variable.

In the arrays method, integer variable, "odd_column_sum, sum_of_Elements, i, j, and even" is defined, in which variable "i and j" is used in the loop for calculating value, even is used to check odd column and then store its value in the "odd_column_sum" variable, and add whole element value is added into the "sum_of_Elements" variable.

8 0
3 years ago
Your boss (the IT director) wants to move several internally developed software applications to an alternate environment, suppor
satela [25.4K]

Answer:

A. PaaS

Explanation:

There are various cloud services like PaaS (platform as a service), IaaS (infrastructure as a service), SaaS (software as a service) etc.

The PaaS is a platform based service where online and adaptive environment is available to run software applications on several digital platforms. Unlike SaaS, it does not provide software services but an environment to install and run other applications.

7 0
3 years ago
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