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3 years ago

How is it that a square is a rectangle but a rectangle ins't a square?

2 answers:

6 0

The definition of a square is a plane figure with four equal straight sides and four right angles. The definition of a rectangle is a plane figure with four right sides and four right angles. To be a rectangle you just need four straight sides and four right angles, but to be a square all those sides have to be equal. Therefore, a square is a rectangle because it has four straight sides and four right angles, but a rectangle isn't a square (or not always) because it doesn't have four equal straight sides.

Helen [10]3 years ago

5 0

Beacuse A square by definition is a "plane figure having four equal sides." Rectangles' sides are not equal and hence cannot be a square.

A rectangle by definition is a "four-sided plane figure with 4 right angles" - which also implies that a square can be a rectangle because it is also a four-sided plane figure with 4 right angles...... hope this helps

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40 percent of what number equals 19.2

worty [1.4K]

You can get the number by dividing 19.2 by 0.40

The number is 19.2/0.40 = 48

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4 years ago

Read 2 more answers

The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain riv

Gelneren [198K]

Answer:

$v_2 \approx 1.12246\ m.s^{-1}$

$v_{10}\approx 1.4678\ m.s^{-1}$

$v_{100}\approx 1.4678\ m.s^{-1}$

Step-by-step explanation:

Mass of particles that a river can transport, $m\propto\ v^6$

where:

v = velocity of river flow

When $v=1\ m.s$

then the mass transported, $m \propto 1^6$

When mass is twice:

$v=\sqrt[6]{2}$

$v_2 \approx 1.12246\ m.s^{-1}$

When mass is 10 times:

$v=\sqrt[6]{10}$

$v_{10}\approx 1.4678\ m.s^{-1}$

When mass is 100 times:

$v=\sqrt[6]{100}$

$v_{100}\approx 1.4678\ m.s^{-1}$

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3 years ago

What is the equation of a parabola with (4, 6) as its focus and y = 2 as its directrix?

antoniya [11.8K]

So hmmm if you notice the picture below

bear in mind that, the vertex is "p" distance from the focus, and "p" distance from the directrix

now, the focus is at 4,6 and the directrix below that, meaning the parabola is vertical and opening upwards

and the vertex is half-way between the focus point and the directrix

$\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
(y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\\\
\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})} \\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-----------------------------\\\\
(x-4)^2=4(2)(y-4)\implies (x-4)^2=8(y-4)
\\\\\\
\cfrac{(x-4)^2}{8}=y-4\implies \cfrac{1}{8}(x-4)^2+4=y$

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4 years ago

Garrett starts his homework at 5:20 he spends 20 minutes or rear and 15 minutes on math at whst time does garrett finish his hom

Whitepunk [10]

The answer is D because 5:20 + 20 + 15 is 5:55

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3 years ago

Pleaseee helppppppp!!!!!!

Softa [21]

Neither because they dont have the same x points so they cant be vertical and they dont have the same y points so it cant be horizontal

6 0

3 years ago

Read 2 more answers