Answer:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Step-by-step explanation:
Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:
Where
and
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64
Using this value we can set up the following equation:
And we have:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Answer:
The answers are actually-
13 + 2 + 9 = 2 + 13 + 9,
[29(14)] + 45 = [14(29)] + 45
Step-by-step explanation: I got it right on egdenuity.
2.64 divided by 6 equals 0.44. one ounce costs 44 cents
9514 1404 393
Answer:
8
Step-by-step explanation:
The product of segment lengths to the near and far circle intersection points is the same for both "secants". AD is a tangent, so the two intersection points are the same point. This gives ...
AD² = AB·AC
144 = AB(AB +10)
We can add 25 to complete the square.
169 = (AB +5)² . . . write as a square
13 = AB +5 . . . . . . positive square root
8 = AB . . . . . . . . . .subtract 5