3 years ago

I need 7-12 please!!!

Mathematics

1 answer:

sergiy2304 [10]3 years ago

6 0

Answer:

number 7 is y= $\frac{-ax+c}{b}$

Step-by-step explanation:

You might be interested in

Please help with these 2 answers i only have 10 minutes left

natta225 [31]

Answer:

1/4 of a pound
4/15 of the flat

Step-by-step explanation:

For number 1:

3/4 ÷ 3 = 0.25
0.25 = 1/4

For number 2:

4/5 ÷ 3 = 4/15

I hope this helps!

5 0

2 years ago

Read 2 more answers

Solve the system by substitution. -8x – 7y = -5 -x = y

Lapatulllka [165]

Substitute y = -x into the first equation:

-8x - 7(-x) = -5

-8x + 7x = -5

-x = -5

x = 5

Substitute x = 5 into y = -x

y = -(5)

y = -5

Answer: x = 5, y = -5

6 0

3 years ago

Read 2 more answers

The following lines are parallel. 4x + 2y = 8 and y = 2x + 4 True False

Alenkasestr [34]

I believe the answer is True ! Hope this helps you

5 0

3 years ago

Read 2 more answers

Look at the graph. What is ?

shepuryov [24]

Answer:

no picture.

Step-by-step explanation:

no picture

4 0

2 years ago

Multiply. Check picture.

VashaNatasha [74]

The answer is $3x^4-13x^3-x^2-11x+6$ .

Solution:

Use algebraic identity: $a^m\times a^n=a^{m+n}$

For example: $x^2\times x=x^{2+1}=x^3$

Given expression $(x^2-5x+2)$ and $(3x^2+2x+3)$ .

To multiply these equations.

$(x^2-5x+2)\times(3x^2+2x+3)$

$=x^2(3x^2+2x+3)-5x(3x^2+2x+3)+2(3x^2+2x+3)$

$=(3x^4+2x^3+3x^2)+(-15x^3-10x^2-15x)+(6x^2+4x+6)$

$=3x^4+2x^3+3x^2-15x^3-10x^2-15x+6x^2+4x+6$

Combine like terms together.

$=3x^4+(2x^3-15x^3)+(3x^2-10x^2+6x^2)-15x+4x+6$

$=3x^4-13x^3-x^2-11x+6$

$(x^2-5x+2)\times(3x^2+2x+3)=3x^4-13x^3-x^2-11x+6$

Hence the answer is $3x^4-13x^3-x^2-11x+6$ .

3 0

3 years ago